Question

我想模拟resttemplate调用，该调用是作为局部变量和调用的交换方法实现的。我嘲笑使用期望，但它调用实际的方法。我错过了什么。请帮帮我。提前致谢

public class ServiceController {
    public String callGetMethod (HttpServletRequest request){
        String url = request.getParameter("URL_TO_CALL");
        HttpHeaders headers = new HttpHeaders();
        headers.setAccept(Arrays.asList(MediaType.APPLICATION_JSON));
        HttpEntity<String> entity = new HttpEntity<String>(headers);
        RestTemplate restTemplate = new RestTemplate();
        ResponseEntity<String> res = restTemplate.exchange(url, HttpMethod.GET, entity, String.class);
        return res.getBody();
    }
}

@RunWith(JMockit.class)
public class ServiceControllerTest {
    @Tested
    private ServiceController controller;
    @Test
    public void callGetMethod (@Mocked HttpServletRequest request, @Mocked RestTemplate restTemplate){
        new NonStrictExpectations() {
        {
            restTemplate.exchange(host,HttpMethod.GET, entity,String.class); returns (new ResponseEntity<String>("success" , HttpStatus.OK));
        }

        ResponseEntity<String> response = controller.callGetMethod(httpServletRequest);

    }
}

Answer 1

我们需要模拟新的RestTemplate（）。这样它就会将模拟对象restTemplate分配给方法局部变量。

@Mocked
RestTemplate restTemplate;

new NonStrictExpectations() {
    {
      new RestTemplate();
      result = restTemplate; 
      restTemplate.exchange(host, HttpMethod.GET, entity, String.class);
      returns(new ResponseEntity<String>("success", HttpStatus.OK));
    }

模拟本地对象不起作用 - jmockit

1 个答案: