Question

func postUser(username: String, pass: String) -> Bool {
            Alamofire.request("https://someAPI.com/auth/login", method: .post, parameters: ["email": contact, "password": pass], encoding: URLEncoding.default, headers: ["Accept":"application/json"]).responseJSON { (response) in

                switch(response.result) {
                    case .success(let value):
                        let json = JSON(value)
                        print("JSON: \(json)")
                        print(json["data"]["result"])
                        return true
                    case .failure(let error):
                        print(error)
                        return false
                }
            }
        }

Answer 1

如果您正在调用Alamofire.request之类的异步方法，那么当这个异步方法结束时，您需要通知closures

尝试使用

func postUser(username: String, pass: String, finishedClosured:@escaping ((Bool)->Void))  {
            Alamofire.request("https://someAPI.com/auth/login", method: .post, parameters: ["email": contact, "password": pass], encoding: URLEncoding.default, headers: ["Accept":"application/json"]).responseJSON { (response) in

                switch(response.result) {
                    case .success(let value):
                        let json = JSON(value)
                        print("JSON: \(json)")
                        print(json["data"]["result"])
                        finishedClosured(true)
                    case .failure(let error):
                        print(error)
                        finishedClosured(false)
                }
            }
        }

使用

 self.postUser(username: "your UserName", pass: "Your Pass") { (result) in
            if(result){
                debugPrint("All is fine")
            }else{
                debugPrint("All is wrong")
            }
        }

Answer 2

您不应该从此方法返回true或false，因为这是异步网络调用，只需使用回调来获取您的数据

func postUser(username: String, pass: String callback: @escaping (Bool) -> Void){
            Alamofire.request("https://someAPI.com/auth/login", method: .post, parameters: ["email": contact, "password": pass], encoding: URLEncoding.default, headers: ["Accept":"application/json"]).responseJSON { (response) in

                switch(response.result) {
                    case .success(let value):
                        let json = JSON(value)
                        print("JSON: \(json)")
                        print(json["data"]["result"])
                        callback(true)  //using this you can send back the data                   

                   case .failure(let error):
                        print(error)
                        callback(false)

                }
            }
           //here you can return true or false but I dont think you should


        }

void函数中的意外非void返回值（Swift 3）

2 个答案: