Question

我正在尝试使用express-fileupload上传文件，并且没有运气让它工作。我可以获取文件（在这种情况下是图片）来上传＆＃39;从某种意义上说，我可以让控制台显示使用正确文件夹上传的图像。

startup.js

router.get('/upload', function(req, res) {
    res.render('upload');
});

router.post('/upload', function(req, res) {
    // The name of the input field (i.e. "sampleFile") is used to retrieve the uploaded file 
  let startup_image = req.files.image;

  // Use the mv() method to place the file somewhere on your server 
  startup_image.mv('/images' , function(err) {
      if(err){
          console.log(err);
      }
  });
});

然后我的html表单是

<form ref='uploadForm' 
      id='uploadForm' 
      action='/upload' 
      method='post' 
      encType="multipart/form-data">
        <input type="file" name="image" />
        <input type='submit' value='Upload!' />
    </form>

Answer 1

您指向文件所在的目录，但您没有给它一个文件名。我想说让用户决定客户端的文件名并将其添加到路径中。

<input name="userFileName" type="text">//userFilename Here</input>
var myFILENAME = req.body.userFilename 
startup_image.mv('/images/'+myFILENAME+'.jpg', ..) //myFILENAME needs to be added here

另请参阅 how to upload files with express-fileupload

中的完整示例

<强>更新

我找到了问题的解决方案，您需要将__dirname添加到此行，以便让程序知道您source代码的当前目录。

startup_image.mv(__dirname + '/images' , function(err) {..

更新2

这是我的源代码，如果您需要，可以尝试使用它。

我的HTML

<!DOCTYPE html>
<html>
  <head>
    <meta charset="utf-8">
    <title></title>
  </head>
  <body>
    <form ref='uploadForm' encType="multipart/form-data" class="" action="/upload" method="post">
      <input type="text" name="fileName" value=""><br>
      <input type="file" name="foo" value=""><br>
      <input type="submit" name="" value="upload!">
    </form>
  </body>
</html>

我的主要来源

var express = require("express);
var app = express();
const fileUpload = require('express-fileupload');
//npm install ejs, express, express-fileupload

//middleware
app.use(express.static(__dirname));
app.set('view engine', 'ejs');
app.use(fileUpload());

app.get('/inputFile', function(req, res){
  res.render('inputt');
});

app.post('/upload', function(req, res) {
  // The name of the input field (i.e. "sampleFile") is used to retrieve the uploaded file
   var startup_image = req.files.foo;
   var fileName = req.body.fileName;
   // Use the mv() method to place the file somewhere on your server
   startup_image.mv(__dirname + '/images/' + fileName + '.jpg' , function(err) {
     if(err){
       console.log(err);
     }else{
    console.log("uploaded");
}
   });
 });

app.listen(7777);

Answer 2

使用异步/等待风格

在您的服务器文件中执行此操作

const fileUpload = require('express-fileupload');

 app.use(
  fileUpload({
    limits: { fileSize: 50 * 1024 * 1024 },
    useTempFiles: true,
   // dir for windows PC
    tempFileDir: path.join(__dirname, './tmp'),
  }),
);

然后在您的控制器中执行此操作

  const file = req.files.filename;
  await file.mv(file.name);

  if (!file || Object.keys(req.files).length === 0) {
    return res.status(400).console.error('No files were uploaded.');
  }

Answer 3

此解决方案适用于非ejs和导出模块解决方案：

<!DOCTYPE html>
<html>
  <head>
    <meta charset="utf-8">
    <title>File Upload</title>
  </head>
  <body>
    <form ref='uploadForm' encType="multipart/form-data" class="" action="/path/to/nodejs/upload/file" method="post">
      <input type="file" name="my_file"><br>
      <input type="submit" name="" value="upload">
    </form>
  </body>
</html>

现在是NodeJS

const express = require("express");
const app = express();
const fileUpload = require('express-fileupload');

app.use(fileUpload({ safeFileNames: true, preserveExtension: true }))

app.post('/', function(req, res) {
    // The name of the input field (i.e. "sampleFile") is used to retrieve the uploaded file
    let the_file = req.files.my_file;

    the_file.mv('/path/to/html/uploads/up/' + the_file.name , function(err) {

        res.writeHead(200, {"Content-Type": "text/plain"});
        if(err){
            console.log(err);
            res.write(err);
            res.end();
        } else {
            console.log("uploaded");
            res.write("upload of file "+the_file.name+" complete");
            res.end();
        } 

   });

});

module.exports = app;

Answer 4

您必须创建文件夹图像！

Answer 5

//install path module 
const path = require('path');

 // remaining code

let startup_image = req.files.image;

startup_image.mv(path.resolve(__dirname,'/images',startup_image.name), function(error){
  //remaining code
})

Answer 6

这样 file.mv（path.resolve（__ dirname，'../public/images'，文件名）

使用express-fileupload上传文件

6 个答案: