这种情况的延续:Can't understand destructuring in JWT auth (Phoenix)
我正在使用JWT与Guardian和Comeonin建立API身份验证。这个动作似乎有效,因为从iex调用user
并将其传递给Guardian.encode_and_sign/2
给了我正在寻找的元组。
def create(conn, %{"session" => session_params}) do
case MyApp.Session.authenticate(session_params) do
{:ok, user} ->
{:ok, jwt, _full_claims} = user |> Guardian.encode_and_sign(:token)
conn
|> put_status(:created)
|> render("show.json", jwt: jwt, user: user)
:error ->
conn
|> put_status(:unprocessable_entity)
|> render("error.json")
end
end
当我发出curl请求时,我在控制台中收到此错误:
[error] #PID<0.565.0> running MyApp.Endpoint terminated
Server: localhost:4000 (http)
Request: POST /api/v1/sessions
** (exit) an exception was raised:
** (Poison.EncodeError) unable to encode value: {nil, "users"}
(poison) lib/poison/encoder.ex:383: Poison.Encoder.Any.encode/2
(poison) lib/poison/encoder.ex:227: anonymous fn/4 in Poison.Encoder.Map.encode/3
(poison) lib/poison/encoder.ex:228: Poison.Encoder.Map."-encode/3-lists^foldl/2-0-"/3
(poison) lib/poison/encoder.ex:228: Poison.Encoder.Map.encode/3
(poison) lib/poison/encoder.ex:227: anonymous fn/4 in Poison.Encoder.Map.encode/3
(poison) lib/poison/encoder.ex:228: Poison.Encoder.Map."-encode/3-lists^foldl/2-0-"/3
(poison) lib/poison/encoder.ex:228: Poison.Encoder.Map.encode/3
(poison) lib/poison/encoder.ex:227: anonymous fn/4 in Poison.Encoder.Map.encode/3
(poison) lib/poison/encoder.ex:228: Poison.Encoder.Map."-encode/3-lists^foldl/2-0-"/3
(poison) lib/poison/encoder.ex:228: Poison.Encoder.Map.encode/3
(poison) lib/poison.ex:41: Poison.encode!/2
(phoenix) lib/phoenix/controller.ex:740: Phoenix.Controller.do_render/4
(myapp) web/controllers/api/v1/sessions_controller.ex:1: MyApp.SessionsController.action/2
我应该寻找什么来解决这个问题?
答案 0 :(得分:3)
看看这个issue。
您正在将私有元数据信息编码到客户端。
但是,Poison
在@derive
属性中有一个:except选项,可以从编码结果中排除一个键:
defmodule User do
@derive {Poison.Encoder, except: [:__meta__]}
end