Question

我只有名为Employee的表名，该表具有所有地址属性，我想使用hibernate employee表和地址属性的内部类进行映射。

<property name="clientMark" column="CLIENT_MARK"/>
<property name="Address.street1" column="B_STREET_ADDRESS_1"/>
<property name="Address.street2" column="B_STREET_ADDRESS_2"/>
<property name="Address.city" column="B_CITY"/>
<property name="Address.state" column="B_STATE"/>
<property name="Address.postalCode" column="B_POSTAL_CODE"/>
<property name="Address.country" column="B_COUNTRY"/>

Answer 1

如果我理解正确，你必须做这样的事情：

public class Employee {
    private String clientMark;
    private Address address;

    public String getClientMark() {
        return clientMark;
    }

    public void setClientMark(String clientMark) {
        this.clientMark = clientMark;
    }

    public Address getAddress() {
        return address;
    }

    public void setAddress(Address address) {
        this.address = address;
    }

    public static class Address {
        private String street1;
        private String street2;

        public String getStreet1() {
            return street1;
        }

        public void setStreet1(String street1) {
            this.street1 = street1;
        }

        public String getStreet2() {
            return street2;
        }

        public void setStreet2(String street2) {
            this.street2 = street2;
        }
    }
}

使内部类public和static能够从其他类创建新对象。然后为外部类中的内部类添加setter和getter方法，hibernate将能够设置并获取对象。接下来，您需要编辑.hbm.xml文件：

    <property name="clientMark" column="CLIENT_MARK"/>
    <component name="address">
        <property name="street1" column="B_STREET_ADDRESS_1"/>
    </component>
    <component name="address">
        <property name="street2" column="B_STREET_ADDRESS_2"/>
    </component>

Hibernate注释<component>表示命名变量将是包含一些变量的类（hbm.xml文件中为<property>）。在此之后，您可以像这样测试您的代码：

    Employee entity = new Employee();
    entity.setClientMark("client_mark");
    Employee.Address address = new Employee.Address();
    address.setStreet1("street1");
    address.setStreet2("street2");
    entity.setAddress(address);
    // entity is ready to be saved

您在数据库中的结果将是：

|------------------------------------------------------------|
| id | CLIENT_MARK | B_STREET_ADDRESS_1 | B_STREET_ADDRESS_2 |
|------------------------------------------------------------|
| 1  | client_mark | street1            | street2            |
|------------------------------------------------------------|

我希望它可以帮助你...☺

如何使用hibernate将嵌套类映射到单个数据库表？

1 个答案: