Question

我一直在寻找，但我找不到如何使用pyhook来响应组合的示例，例如 Ctrl + C < / kbd>虽然很容易找到如何单独响应单个按键的示例，例如 Ctrl 或 C 。

BTW，我在谈论Windows XP上的Python 2.6。

任何帮助表示感谢。

Answer 1

您是否尝试过使用HookManager中的GetKeyState方法？我没有测试过代码，但它应该是这样的：

from pyHook import HookManager
from pyHook.HookManager import HookConstants

def OnKeyboardEvent(event):
    ctrl_pressed = HookManager.GetKeyState(HookConstants.VKeyToID('VK_CONTROL') >> 15)
    if ctrl_pressed and HookConstant.IDToName(event.keyId) == 'c': 
        # process ctrl-c

这是further documentation on GetKeyState

Answer 2

实际上Ctrl + C拥有自己的Ascii代码（即3）。这样的事情对我有用：

import pyHook,pythoncom

def OnKeyboardEvent(event):
    if event.Ascii == 3:
        print "Hello, you've just pressed ctrl+c!"

Answer 3

您可以使用以下代码来观察pyHook返回的内容：

import pyHook
import pygame

def OnKeyboardEvent(event):
    print 'MessageName:',event.MessageName
    print 'Ascii:', repr(event.Ascii), repr(chr(event.Ascii))
    print 'Key:', repr(event.Key)
    print 'KeyID:', repr(event.KeyID)
    print 'ScanCode:', repr(event.ScanCode)
    print '---'

hm = pyHook.HookManager()
hm.KeyDown = OnKeyboardEvent
hm.HookKeyboard()

# initialize pygame and start the game loop
pygame.init()
while True:
    pygame.event.pump()

使用它，似乎pyHook返回

c:      Ascii 99, KeyID 67,  ScanCode 46
ctrl:   Ascii 0,  KeyID 162, ScanCode 29
ctrl+c: Ascii 3,  KeyID 67,  ScanCode 46

（Python 2.7.1，Windows 7，pyHook 1.5.1）

Answer 4

我没有任何其他答案的运气，所以这就是我做的事情

class Keystroke_Watcher:
    def __init__(self, master):
        self.hm = HookManager()
        self.hm.KeyDown = self.on_key_down
        self.hm.KeyUp = self.on_key_up
        self.hm.HookKeyboard()
        self.keys_held = set()  # set of all keys currently being pressed

    def get_key_combo_code(self):
        # find some way of encoding the presses.
        return '+'.join([HookConstants.IDToName(key) for key in self.keys_held])

    def on_key_down(self, event):
        try:
            self.keys_held.add(event.KeyID)
        finally:
            return True

    def on_key_up(self, event):
        keycombo = self.get_key_combo_code()
        print(keycombo)
        try:
            # Do whatever you want with your keycombo here
        finally:
            self.keys_held.remove(event.KeyID)
            return True

    def shutdown(self):
        PostQuitMessage(0)
        self.hm.UnhookKeyboard()

使用pyhook来响应组合键（不只是单击键）？

4 个答案: