在Shell脚本中声明数组时出错

Question

我有一个脚本，我正逐行将文件读入数组。

#!/bin/bash
echo "Enter audio file name. (File must be of .wav format)"

read fileName

echo "Enter path of the audio file"

read path

echo "Enter folder name"

read outputfolder 

mkdir -p $outputfolder

echo "Processing $fileName"
./ilp_diarization2.sh $path/$fileName.wav 120 $outputfolder


#value="$(grep "$fileName.*S" $outputfolder/$fileName/$fileName.g.3.seg)"


#echo "${value}"

awk '{ print $3" "$4}' $outputfolder/$fileName/$fileName.g.3.seg > a

#var=$(awk '{ print $1 }' a) > 2

#echo "${var[0]}


getArray() {
    array=() # Create array
    while IFS= read -r line # Read a line
    do
        array+=("$line") # Append line to the array
    done < "$1"
}

getArray "a" #file name

我遇到的错误是数组减速。

Syntax error: "(" unexpected (expecting "}")

我尝试过使用

array="()"

但它们似乎都不起作用。

以下是文件的内容：

S0 [
42 4677
S10 [
4719 1266
6020 3618
9667 8463

Answer 1

似乎您的版本不支持数组，否则readarray是内置的bash并且与函数相同

help readarray

readarray -t my_array < filename