Question

我有这个数组（更长的时间 - 只有部分）

  [366] => Array
    (
        [0] => 8
        [1] => 7
        [2] => 8
        [3] => 9
        [4] => 8
    )

[367] => Array
    (
        [0] => 8
        [1] => 9
        [2] => 9
        [3] => 10
        [4] => 10
        [5] => 9
        [6] => 8
        [7] => 9
        [8] => 10
        [9] => 10
        [10] => 11
        [11] => 10
        [12] => 11
        [13] => 11
        [14] => 10
        [15] => 9
        [16] => 10
        [17] => 8
        [18] => 10
    )

必须保留密钥（有一个id）。我想总结一下foreach的值（在这个例子中，值是代数）。所以第8代计算为366次计数3次。

期望是id 366：7 - 1x，8 - 3x，9 - 1x或

    [366] => Array
   (
    [7] => 1
    [8] => 3
    [9] => 1
   )

  [367] => Array
  (
    [8] => 3
    [9] => 5
    [10] => 8
    [11] => 3
   )

每个建议都受到欢迎和赞赏！

我总是用数字键或foreach停止...我试过的代码之一：

$outdams = array(); 
foreach ($dams as $key => $value) {
    foreach ($value as $key2 => $value2) {
        $index = $value2;
        if (array_key_exists($index, $outdams)) {
            $outdams[$index]++;
        } else {
            $outdams[$index] = 1;
        }
    }
}

Answer 1

检查此代码

<?php
$data = array(366=>array(8,7,8,8,9),
              367=>array(8,9,13,14,17,14)); 
echo "<pre>"; print_r($data);

$response = array(); 
foreach ($data as $outerkey => $outerData){
    foreach ($outerData as $innerkey => $innerData){
        //echo "<pre>"; print_r($innerData);
        if(array_key_exists($innerData, $response[$outerkey])){
            $response[$outerkey][$innerData] ++;
        }else{
            $response[$outerkey][$innerData] = 1;
        }
    }   
}
echo "<pre>"; print_r($response); 

?>

NUM。数组，总和相同的值php

1 个答案: