Question

不同地请求您的帮助我正在尝试使用搜索栏过滤表格视图，但我得到的数据不在正确的位置，我曾多次尝试弄明白，但没有任何机会，我得到的结果只是第一行无关紧要我输入哪个房间号码我粘贴了下面的代码，非常感谢您的帮助

final let urlString = "http://ccm-hotels.com/ccmandroid/api/getteams.php"

@IBOutlet weak var tableView: UITableView!
@IBOutlet weak var searchBar: UISearchBar!

@IBAction func BackToMenu(_ sender: UIBarButtonItem) {
    let MainMenu = self.storyboard?.instantiateViewController(withIdentifier: "MainMenu") as! MainMenu
    self.navigationController?.pushViewController(MainMenu, animated: true)
}


    var openCaseRoomArray: [String] = []
    var openCaseNameArray: [String] = []



var openCaseRoomArrayF: [String] = []

var inSearchMode = false

override func viewDidLoad() {
    super.viewDidLoad()

    tableView.delegate = self
    tableView.dataSource = self
    searchBar.delegate = self
    searchBar.returnKeyType = UIReturnKeyType.done
    openCaseRoomArrayF = openCaseRoomArray

    let alertController = UIAlertController(title: nil, message: "Please wait\n\n", preferredStyle: .alert)
    let spinnerIndicator = UIActivityIndicatorView(activityIndicatorStyle: .whiteLarge)
    spinnerIndicator.center = CGPoint(x: 135.0, y: 65.5)
    spinnerIndicator.color = UIColor.black
    spinnerIndicator.startAnimating()
    alertController.view.addSubview(spinnerIndicator)
    self.present(alertController, animated: false, completion: nil)
    let when = DispatchTime.now() + 5
    DispatchQueue.main.asyncAfter(deadline: when){
        // your code with delay
        alertController.dismiss(animated: true, completion: nil);}


    self.downloadJsonWithURL()

    // Do any additional setup after loading the view, typically from a nib.
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}


func downloadJsonWithURL() {
    let url=URL(string:"http://ccm-hotels.com/ccmandroid/api/getteams.php")
    do {
        let allContactsData = try Data(contentsOf: url!)
        let allContacts = try JSONSerialization.jsonObject(with: allContactsData, options: JSONSerialization.ReadingOptions.allowFragments) as! [String : AnyObject]
        if let arrJSON = allContacts["CurrentOpenCases"] {
            for index in 0...arrJSON.count-1 {
                let aObject = arrJSON[index] as! [String : AnyObject]

                if let Room = aObject["RoomNumber"] as? String {
                    openCaseRoomArray.append(Room)
                }
                if let Name = aObject["GuestName"] as? String {
                    openCaseNameArray.append(Name)
                }

            }
        }

        self.tableView.reloadData()
    }
    catch {

    }
}


func numberOfSections(in tableView: UITableView) -> Int {
    return 1
}


func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    if inSearchMode {
        return openCaseRoomArrayF.count
    }
    return openCaseRoomArray.count
}


func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "cell") as! TableViewCell

    if inSearchMode {
        cell.openCaseRoom.text = self.openCaseRoomArrayF[indexPath.row]
        cell.openCaseName.text = self.openCaseNameArray[indexPath.row]

    }else{
    cell.openCaseRoom.text = self.openCaseRoomArray[indexPath.row]
    cell.openCaseName.text = self.openCaseNameArray[indexPath.row]


}
     return cell

}

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {   
   let vc = self.storyboard?.instantiateViewController(withIdentifier: "DetailViewController") as! DetailViewController


    vc.dopenCaseRoomString = openCaseRoomArray[indexPath.row]
    vc.openCaseNameString = openCaseNameArray[indexPath.row]



    self.navigationController?.pushViewController(vc, animated: true)
}


func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
    if searchBar.text == nil || searchBar.text == "" {
        inSearchMode = false
        view.endEditing(true)
        tableView.reloadData()
    } else {
        inSearchMode = true
        openCaseRoomArrayF = openCaseRoomArray.filter({$0 == searchBar.text})
        tableView.reloadData()
    }
}

}

Answer 1

在func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell方法中，当您在self.openCaseNameArray更新搜索结果时，您会显示self.openCaseRoomArrayF的名称。当您获得api响应时，您将在两个阵列中分配空间及其相应的名称，但是当您在self.openCaseRoomArrayF中搜索并更新搜索结果时，索引会发生变化。现在 openCaseNameArray 和 openCaseRoomArray 处于匹配索引中，但 openCaseNameArray 和 openCaseRoomArrayF 不在同一匹配索引中。因此，如果您从openCaseNameArray腾出空间，则无法在openCaseRoomArrayF中获得相应的名称。

尝试制作一个班级（例如房间）并将房间班级object存储在array中。从array搜索并显示。无需维护数组。

搜索栏过滤错误的数据

1 个答案: