Question

我正在尝试对字母数字值列表进行排序，换言之，包含数字和字符串的列表

示例：BOB10，BOT20，ETC ......

List<Object> myList = _items.OrderBy(x => x.FirstName).ToList();
_items= new List<Object>(myList);

但输出仍然是：BOT20，BOB10

出了什么问题？

Answer 1

第一：尝试使用字母数字算法，首先在新类中实现算法，而不是这样做：

List<Object> yourList = new List < Object >(thePreviousList.OrderBy(x => x.FirstName, new AlphanumComparatorFast()).ToList())

正如这里所解释的那样：

http://www.dotnetperls.com/alphanumeric-sorting

通过创建新类来实现算法 AlphanumComparatorFast ，而不仅仅是调用它

编辑：

下面的alpha算法：

Public class AlphanumComparatorFast : IComparer
{
    public int Compare(object x, object y)
    {
        string s1 = x as string;
        if (s1 == null)
        {
            return 0;
        }
        string s2 = y as string;
        if (s2 == null)
        {
            return 0;
        }

        int len1 = s1.Length;
        int len2 = s2.Length;
        int marker1 = 0;
        int marker2 = 0;

        // Walk through two the strings with two markers.
        while (marker1 < len1 && marker2 < len2)
        {
            char ch1 = s1[marker1];
            char ch2 = s2[marker2];

            // Some buffers we can build up characters in for each chunk.
            char[] space1 = new char[len1];
            int loc1 = 0;
            char[] space2 = new char[len2];
            int loc2 = 0;

            // Walk through all following characters that are digits or
            // characters in BOTH strings starting at the appropriate marker.
            // Collect char arrays.
            do
            {
                space1[loc1++] = ch1;
                marker1++;

                if (marker1 < len1)
                {
                    ch1 = s1[marker1];
                }
                else
                {
                    break;
                }
            } while (char.IsDigit(ch1) == char.IsDigit(space1[0]));

            do
            {
                space2[loc2++] = ch2;
                marker2++;

                if (marker2 < len2)
                {
                    ch2 = s2[marker2];
                }
                else
                {
                    break;
                }
            } while (char.IsDigit(ch2) == char.IsDigit(space2[0]));

            // If we have collected numbers, compare them numerically.
            // Otherwise, if we have strings, compare them alphabetically.
            string str1 = new string(space1);
            string str2 = new string(space2);

            int result;

            if (char.IsDigit(space1[0]) && char.IsDigit(space2[0]))
            {
                int thisNumericChunk = int.Parse(str1);
                int thatNumericChunk = int.Parse(str2);
                result = thisNumericChunk.CompareTo(thatNumericChunk);
            }
            else
            {
                result = str1.CompareTo(str2);
            }

            if (result != 0)
            {
                return result;
            }
        }
        return len1 - len2;
    }
}

Answer 2

为什么不使用List.Sort（）而不是OrderBy？

using System;
using System.Collections.Generic;

namespace Test {
    static class Program {
        static void Main() {
            List<string> list = new List<string>() {"BOT20", "BOB10", "BUG40", "BAG90"};
            list.Sort();
            foreach(var el in list)  {
                Console.Write(el + ">");
            }
        }
    }
}

输出：BAG90>BOB10>BOT20>BUG40>

当数组列表包含字符串时，它没有正确排序

2 个答案: