如何计算ID的组/字段值的数量？

Question

我有一个详细的表格，其中我想计算具有2个或更多不同action_taken值的user_ids。

详情：

| user_id | action_taken          | action_date |
|---------|-----------------------|-------------|
| 1234    | clicked on a link     | 1/1/2017    |
| 1234    | went to the home page | 1/5/2017    |
| 1234    | clicked on a link     | 1/7/2017    |
| 1234    | clicked on a link     | 1/9/2017    |
| 1234    | changed password      | 1/11/2017   |
| 1234    | clicked on a link     | 1/13/2017   |
| 9876    | went to the home page | 2/1/2017    |
| 9876    | went to the home page | 2/5/2017    |
| 9876    | went to the home page | 2/7/2017    |
| 9876    | went to the home page | 2/9/2017    |
| 5566    | clicked on a link     | 1/1/2017    |
| 5566    | clicked on a link     | 1/5/2017    |
| 5566    | changed password      | 1/7/2017    |
| 5566    | clicked on a link     | 1/9/2017    |
| 4433    | went to the home page | 1/5/2017    |

期望的输出：

输出1：返回actions_taken的不同值的数量。

| user_id | number_dift_action_taken_values |
|---------|---------------------------------|
| 1234    | 3                               |
| 4433    | 1                               |
| 5566    | 2                               |
| 9876    | 1                               |

输出2：仅返回具有＆gt; = 2个不同action_taken值的user_ids。

| user_id |
|---------|
| 1234    |
| 5566    |

到目前为止，这是我无法正常工作的内容：http://rextester.com/TUL87833。 HAVING子句计算属于每个组的详细信息中的行数，不 GROUP BY user_id，action_taken子句...

指定的组数

select
    user_id
    ,action_taken
    ,count(*)
from
    tbl
group by
    user_id
    ,action_taken
having count(*) >=2;

| user_id | action_taken          | count |
|---------|-----------------------|-------|
| 1234    | clicked on a link     | 4     |
| 5566    | clicked on a link     | 3     |
| 9876    | went to the home page | 4     |

Answer 1

输出1

SELECT user_id,
       COUNT(DISTINCT action_taken) number_dift_action_taken_values
  FROM t_tab
 GROUP BY user_id

结果

user_id number_dift_action_taken_values
1234    3
4433    1
5566    2
9876    1

输出2

SELECT user_id
  FROM t_tab
 GROUP BY user_id
HAVING COUNT(DISTINCT action_taken) >= 2

结果

user_id
1234
5566

Answer 2

对于每个输出＃：

，我会从以下内容开始

输出1：

select 
user_id
,count(distinct action_taken) as number_dift_action_taken_values
into #Output1_tbl
from details_tbl 
group by user_id

输出2：

select *
from #Output1_tbl
where number_dift_action_taken_values >= 2