Question

我的php函数有点问题。我花了很多时间找到错误，但没有成功。由于我非常新的更多＆＃34;复杂＆＃34; php编程，我可能会错过这个错误。

简短说明。

我已经创建了一个函数（用header.php编写），用于将用户活动插入到我的数据库中。代码如下

function userLog($type, $information){

    include_once 'inc/dbconnect.inc.php';

    $types = array("signup" => "",
                   "login" => "", 
                   "logout_manual" => "", 
                   "password_change" => "",
                   "password_reset_sendMail" => "Sent to: '".isset($information['mail']) ? $information['mail'] : "" ."'",
                   "password_reset_setNew" => "",
                   "mail_change_sendMail" => "Sent to: '".isset($information['mail']) ? $information['mail'] : ""."'",
                   "mail_change_verify" => "Changed from ".isset($information['old_mail']) ? $information['old_mail'] : ""." to ".isset($information['mail']) ? $information['mail'] : "");


    $user_uid = $_SESSION['u_uid'];
    $action = $type;
    $description = $types[$type];
    $date = date("Y-m-d H:i:s");
    $browser  = $_SERVER[HTTP_USER_AGENT]; 

    $sql = "INSERT INTO userlogs (userlog_user_uid, userlog_action, userlog_action_description, userlog_date, userlog_browser) VALUES ('$user_uid', '$action', '$description', '$date', '$browser')";
    mysqli_query($conn, $sql);

}

现在我想在登录脚本中调用该函数，如果用户已成功登录的话。它看起来像这样：

if (isset($_POST['login_submit'])) {

include_once 'inc/dbconnect.inc.php';

$uid = mysqli_real_escape_string($conn, $_POST['uid']);
$pwd = mysqli_real_escape_string($conn, $_POST['pwd']);

$_SESSION['inputs'] = array("uid" => $_POST['uid']);

//Check if inputs are empty
if (empty($uid) || empty($pwd)) {
    $_SESSION['error'] = array("Bitte alle Felder ausfüllen!");
    header("Location: ".$_SERVER['HTTP_REFERER']);
    exit();
} else {
    $sql = "SELECT * FROM users WHERE user_uid='$uid' OR user_mail='$uid'";
    $result = mysqli_query($conn, $sql);
    $resultCheck = mysqli_num_rows($result);        

    if ($resultCheck < 1) {
        $_SESSION['error'] = array("Benutzername/E-Mail und/oder Passwort sind falsch!");
        header("Location: ".$_SERVER['HTTP_REFERER']);
        exit();
    } else {
        while ($row = mysqli_fetch_assoc($result)) {
            //De-hashing the password
            $hashedPwdCheck = password_verify($pwd, $row['user_pwd']);
            if ($hashedPwdCheck == false) {
                $_SESSION['error'] = array("Benutzername/E-Mail und/oder Passwort sind falsch!");
                header("Location: ".$_SERVER['HTTP_REFERER']);
                exit();
            } elseif ($hashedPwdCheck == true) {
                //Log in the user here
                $_SESSION['u_id'] = $row['user_id'];
                $_SESSION['u_uid'] = $row['user_uid'];
                $_SESSION['u_email'] = $row['user_email'];

                $information = array();
                userLog("login", $information);

                header("Location: ".$root."index/index");
                exit();
            } else {
                $_SESSION['error'] = array("Benutzername/E-Mail und/oder Passwort sind falsch!");
                header("Location: ".$_SERVER['HTTP_REFERER']);
                exit();
            }
        }
    }
}
} else {
header("Location: ".$root."account/login");
exit();
}

这是＆＃34;奇怪的＆＃34;事情。如果我在logout form-action脚本中调用它，我的功能正在运行。

if (isset($_POST['logout_submit'])) {

   $information = array();
   userLog("logout_manual", $information);

   session_unset();
   session_destroy();
   header("Location: ".$root);
   exit();
}

所以我的功能实际上运行正常。但它只是从注销脚本中工作。如果我想在我的登录脚本和我的注册脚本中调用它，它不起作用。我也尝试在登录脚本本身而不是header.php中声明该函数，但它也没有用。所以我认为根据这些信息，我的登录/注册脚本中存在错误，但我无法找到它。

也许有些人有个主意。

php-function不会在某些表单 - 动作脚本中执行

0 个答案: