我有下表:
id tax rate quantity
1 20 400 5
2 20 566 2
3 5 200 4
这是我的预期输出:
taxableamount taxamount total
3132.00 626.40 3758.40
800.00 40.00 840.00
让我在这里解释一下我的尝试:
如果每一行具有相同的税额,我计算了每行数据的金额(rate × quantity
),然后计算税额(amount × tax ÷ 100)
并将结果显示在一行中,即使它们是来自多行。但如果行没有相同的税值,它将显示在单独的行中。
$query = "SELECT SUM(
CASE WHEN tax=tax
THEN rate*quantity ELSE 0 END) AS taxableamount,
SUM(CASE WHEN tax=tax
THEN (rate*quantity)+(rate*quantity)*tax/100 ELSE 0 END) AS tax,
SUM(CASE WHEN tax=tax
THEN (rate*quantity)*tax/100 ELSE 0 END) AS taxamount,
SUM(CASE WHEN tax=tax
THEN (rate*quantity)+(rate*quantity)*tax/100 ELSE 0 END) AS total
FROM pricing group by tax";
while($row = show($query)):
echo '<td>'.$row->taxableamount.'</td>';
echo '<td>'.$row->taxamount.'</td>';
echo '<td>'.$row->total.'</td>';
endwhile;
上面的代码给了我错误和意想不到的结果。所以看看我的预期输出,我该怎么做呢。请帮忙。
答案 0 :(得分:5)
您应该删除CASE语句。正如我在评论中所说,税收总是等于税收,因为你正在与同一行进行比较。我添加了税栏,因此您知道每种税的金额:
SELECT
SUM(rate * quantity) AS taxableamount,
SUM(rate * quantity * tax / 100) AS taxamount,
SUM(rate * quantity * (1 + tax) / 100) AS total,
tax
FROM
pricing
GROUP BY
tax
答案 1 :(得分:0)