Question

我正在研究SQL Server 2008 R2 Enterprise，我一直在研究密码生成器，它会自动更改所提供用户名的SQL密码。我在另一个位置找到了脚本并对其进行了一些修改。我遇到的问题是，当我运行脚本时，它会出错。下面是代码，之后是错误。

set nocount on

declare @PASSWORD_MIN_LENGTH    int
declare @PASSWORD_MAX_LENGTH    int
declare @LOGIN          SYSNAME

select @PASSWORD_MIN_LENGTH = 25
select @PASSWORD_MAX_LENGTH = 25
select @LOGIN = 'Test_User'

declare @PASSWORD_DATA table (PASSWORD_CHAR VARCHAR(1) )
declare @NUM table ( DIGIT int not null primary key clustered)

insert into @NUM (DIGIT)
    select DIGIT =  0 union all select DIGIT =  1 union all
    select DIGIT =  2 union all select DIGIT =  3 union all
    select DIGIT =  4 union all select DIGIT =  5 union all
    select DIGIT =  6 union all select DIGIT =  7 union all
    select DIGIT =  8 union all select DIGIT =  9
    order by 1

insert into @PASSWORD_DATA (PASSWORD_CHAR)
select
    PASSWORD_CHAR = 
    substring(b.CHARACTERS,a.RAND_INT%b.MOD,1)
from
    (select
         aa.NUMBER,
         RAND_INT = abs(convert(int, convert(varbinary(100), newid())))
     from
         (select
              NUMBER = a.DIGIT+(b.DIGIT*10)
          from
              @NUM a    
          cross join 
              @NUM b) aa
) a
cross join
    (select
         MOD = len(bb.CHARACTERS)-1,
         bb.CHARACTERS
     from
         (select
              CHARACTERS = 'ABCDEFGHJKLMNPQURSUVWXYZ' +
                           'abcdefghjkmnpqursuvwxyz' +
                           'ABCDEFGHJKLMNPQURSUVWXYZ' +
                           'abcdefghjkmnpqursuvwxyz' +
                           'ABCDEFGHJKLMNPQURSUVWXYZ'+
                           'abcdefghjkmnpqursuvwxyz' +
                           'ABCDEFGHJKLMNPQURSUVWXYZ'+
                           'abcdefghjkmnpqursuvwxyz' +
                           '23456789'+
                           '23456789'+
                           '23456789'+
                           '23456789'+
                           '23456789'+
                           '23456789'+
                           '23456789'+
                           '23456789'+
                           '23456789'+
                           '23456789'+
                           '@#$^*+=<>?'+
                           '@#$^*+=<>?'+
                           '@#$^*+=<>?'+
                           '@#$^*+=<>?') bb
     ) b
order by
    newid()

--select * from @PASSWORD_DATA

declare @password varchar(100)

select @password = ''

select @password = @password+PASSWORD_CHAR
from @PASSWORD_DATA

select @password = 
    -- Random length from MIN to MAX characters
    substring(@password,1,
    @PASSWORD_MIN_LENGTH +
    (abs(convert(int,convert(varbinary(100),newid()))))%(@PASSWORD_MAX_LENGTH -@PASSWORD_MIN_LENGTH+1)) 

print 
'

PASSWORD = '+@password+'


exec master.dbo.sp_password
    @old = NULL ,
    @new = '''+@password+''', 
    @loginame = '''+isnull(@LOGIN,'''')+'''

    '

    exec master.dbo.sp_password
    @old = NULL ,
    @new = '''+@password+''', 
    @loginame = '''+isnull(@LOGIN,'''')+'''

exec master.dbo.sp_password运行后，它会出现以下错误。

Msg 15007，Level 16，State 1，Procedure sp_password，Line 142
''isnull（@LOGIN，''）+''不是有效的登录信息，或者您没有权限。

我希望将其转换为存储过程，以便在被问到时自动生成和更改SQL密码。任何帮助，将不胜感激。 PS。我是盒子里的系统管理员。

Answer 1

以这种方式尝试：

IF @LOGIN IS NOT NULL
exec master.dbo.sp_password
@old = NULL ,
@new = @password, 
@loginame = @LOGIN

Answer 2

这可能是您需要一些动态SQL的地方：

set nocount on
declare @PASSWORD_MIN_LENGTH    int
declare @PASSWORD_MAX_LENGTH    int
declare @LOGIN          SYSNAME
select @PASSWORD_MIN_LENGTH = 25
select @PASSWORD_MAX_LENGTH = 25
select @LOGIN = 'Test_User'

declare @PASSWORD_DATA table (PASSWORD_CHAR VARCHAR(1) )
declare @NUM table ( DIGIT int not null primary key clustered)

----------------------------
DECLARE @TSQL NVARCHAR(4000);
-----------------------------

insert into @NUM (DIGIT)
select DIGIT =  0 union all select DIGIT =  1 union all
select DIGIT =  2 union all select DIGIT =  3 union all
select DIGIT =  4 union all select DIGIT =  5 union all
select DIGIT =  6 union all select DIGIT =  7 union all
select DIGIT =  8 union all select DIGIT =  9
order by 1

insert into @PASSWORD_DATA (PASSWORD_CHAR)
select
    PASSWORD_CHAR = 
    substring(b.CHARACTERS,a.RAND_INT%b.MOD,1)
from
(
select
    aa.NUMBER,
    RAND_INT    = 
    abs(convert(int,convert(varbinary(100),newid())))
from
    (
    select
        NUMBER = a.DIGIT+(b.DIGIT*10)
    from
        @NUM a  cross join @NUM b
    ) aa
) a
cross join
(
select
    MOD = len(bb.CHARACTERS)-1,
    bb.CHARACTERS
from
    (
    select
        CHARACTERS =
        'ABCDEFGHJKLMNPQURSUVWXYZ'+
        'abcdefghjkmnpqursuvwxyz'+
        'ABCDEFGHJKLMNPQURSUVWXYZ'+
        'abcdefghjkmnpqursuvwxyz'+
        'ABCDEFGHJKLMNPQURSUVWXYZ'+
        'abcdefghjkmnpqursuvwxyz'+
        'ABCDEFGHJKLMNPQURSUVWXYZ'+
        'abcdefghjkmnpqursuvwxyz'+
        '23456789'+
        '23456789'+
        '23456789'+
        '23456789'+
        '23456789'+
        '23456789'+
        '23456789'+
        '23456789'+
        '23456789'+
        '23456789'+
        '@#$^*+=<>?'+
        '@#$^*+=<>?'+
        '@#$^*+=<>?'+
        '@#$^*+=<>?'
    ) bb
) b
order by
    newid()

--select * from @PASSWORD_DATA

declare @password varchar(100)

select @password = ''

select @password = @password+PASSWORD_CHAR
from @PASSWORD_DATA

select @password = 
    -- Random length from MIN to MAX characters
    substring(@password,1,
    @PASSWORD_MIN_LENGTH +
    (abs(convert(int,convert(varbinary(100),newid()))))%(@PASSWORD_MAX_LENGTH -@PASSWORD_MIN_LENGTH+1)) 

print 
'

PASSWORD = '+@password+'


exec master.dbo.sp_password
    @old = NULL ,
    @new = '''+@password+''', 
    @loginame = '''+isnull(@LOGIN,'''')+'''

    '
----------------------------------------------  
SELECT @TSQL = '
exec master.dbo.sp_password
    @old = NULL ,
    @new = '''+@password+''', 
    @loginame = '''+isnull(@LOGIN,'''')+''''

EXECUTE sp_executesql @TSQL
----------------------------------------------

密码更改的动态SQL语法问题

2 个答案: