Question

大家好，我在这个问题上需要你的帮助，重点是：

我有两个相关实体“Cargo”和“CatVal”，见下图：

CARGO (Key: ShipCargoId)   CATVAL (Key: CatValId)
+++++++++++++++++++++++++  ++++++++++++++++++++++++
+ ShipCargoId + CargoId +  +CatValId + CatValDesc +
+++++++++++++++++++++++++  ++++++++++++++++++++++++
+     3       +     1   +  +    1    + Cargo 1    +
+++++++++++++++++++++++++  ++++++++++++++++++++++++

好的，在此图中注意这些相关实体在ShipCargoId.CargoId和CatVal.CatValId之间存在关系，这些关系在我的实体文件中配置如何从CatVal到Cargo的OneToMany关系，如下所示：

namespace OLO\CargoBundle\Entity;

use Doctrine\ORM\Mapping as ORM;

/**
 * Cargo
 *
 * @ORM\Table(name="shipcargos")
 * @ORM\Entity(repositoryClass="OLO\CargoBundle\Entity\CargoRepository")
 * @ORM\HasLifecycleCallbacks()
 */
class Cargo
{

/**
 * @ORM\ManyToOne(targetEntity="OLO\CatalogBundle\Entity\CatVal", inversedBy="cargos")
 * @ORM\JoinColumn(name="CargoId", referencedColumnName="CatValId")
 */
protected $cargoId;

/**
 * @var integer
 *
 * @ORM\Column(name="ShipCargoId", type="integer")
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="AUTO")
 */
private $shipCargoId;

 /**
 * Get id
 *
 * @return integer 
 */
public function getShipCargoId()
{
    return $this->shipCargoId;
}

/**
 * Set cargoId
 *
 * @param \OLO\CatalogBundle\Entity\CatVal $cargoId
 * @return Cargo
 */
public function setCargoId(\OLO\CatalogBundle\Entity\CatVal $cargoId = null)
{
    $this->cargoId = $cargoId;

    return $this;
}

/**
 * Get cargoId
 *
 * @return \OLO\CatalogBundle\Entity\CatVal 
 */
public function getCargoId()
{
    return $this->cargoId;
}

}

namespace OLO\CatalogBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;

/**
 * CatVal
 *
 * @ORM\Table(name="catval")
 * @ORM\Entity(repositoryClass="OLO\CatalogBundle\Entity\CatValRepository")
 */
  class CatVal
{
/**
 * @ORM\OneToMany(targetEntity="OLO\CargoBundle\Entity\Cargo", 
    mappedBy="cargoId")
 */
protected $cargos;

/**
 * @var integer
 *
 * @ORM\Column(name="CatValId", type="integer")
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="AUTO")
 */
private $catValId;

/**
 * @var string
 *
 * @ORM\Column(name="CatValDesc", type="string", length=50)
 */
private $catValDesc;

/**
 * Constructor
 */
public function __construct()
{
    $this->cargos = new ArrayCollection();
}

/**
 * Get catValId
 *
 * @return integer 
 */
public function getCatValId()
{
    return $this->catValId;
}

/**
 * Set catValDesc
 *
 * @param string $catValDesc
 * @return CatVal
 */
public function setCatValDesc($catValDesc)
{
    $this->catValDesc = $catValDesc;

    return $this;
}

/**
 * Get catValDesc
 *
 * @return string 
 */
public function getCatValDesc()
{
    return $this->catValDesc;
}

/**
 * Add cargos
 *
 * @param \OLO\CargoBundle\Entity\Cargo $cargos
 * @return CatVal
 */
public function addCargo(\OLO\CargoBundle\Entity\Cargo $cargos)
{
    $this->cargos[] = $cargos;

    return $this;
}

/**
 * Remove cargos
 *
 * @param \OLO\CargoBundle\Entity\Cargo $cargos
 */
public function removeCargo(\OLO\CargoBundle\Entity\Cargo $cargos)
{
    $this->cargos->removeElement($cargos);
}

/**
 * Get cargos
 *
 * @return \Doctrine\Common\Collections\Collection 
 */
public function getCargos()
{
    return $this->cargos;
}
}

然后，我需要生成一个带有实体字段的表单，标签为“CatValDesc”，值为“ShipCargoId”

要实现此目的，我在FormType文件中配置查询构建器，如下所示：

>add('shipCargos', 'entity', array(
                                                'class'  => 'OLOCatalogBundle:CatVal',
                                                'query_builder' => function (EntityRepository $er) use($ShipId){
                                                    return $er->createQueryBuilder('c')
                                                              ->addSelect('c.shpCargoId','p.catValDesc')
                                                              ->leftJoin('c.cargos', 'p', Join::WITH, 'c.catValId = p.cargoId')
                                                              ->where('p.shipId = :id')
                                                              ->setParameter('id', $ShipId);
                                                },
                                                'choice_label' => 'catValDesc',
        ))

但是我无法让它发挥作用，现在告诉我的错误是：

Warning: spl_object_hash() expects parameter 1 to be object, integer given

in vendor/doctrine/orm/lib/Doctrine/ORM/UnitOfWork.php at line 1189   -

 */
public function isScheduledForInsert($entity)
{
    return isset($this->entityInsertions[spl_object_hash($entity)]);
}
/**

 at ErrorHandler ->handleError ('2', 'spl_object_hash() expects parameter 1 
 to be object, integer given', '/home/ubuntu/workspace/vendor/doctrine/orm/lib/Doctrine/ORM/UnitOfWork.php', '1189', array('entity' => '45'))

at spl_object_hash ('45')

如果我更改addSelect for - ＆gt; addSelect（'c'，'p'）来检索intities而不是整数值，请显示以下错误：

Neither the property "shipCargoId" nor one of the methods "getShipCargoId()", "shipCargoId()", "isShipCargoId()", "hasShipCargoId()", "__get()" exist and have public access in class "OLO\CatalogBundle\Entity\CatVal".

那么，任何想法如何让它像魅力一样工作？最好的问候

Answer 1

哟不需要选择ID而是整个实体，表单构建器会为您获取ID。您的查询构建器应如下所示：

'query_builder' => function (EntityRepository $er) use($ShipId){
    return $er->createQueryBuilder('c')
        ->join('c.cargos', 'cg')
        ->where('cg.shipCargoId = :id')
        ->setParameter('id', $ShipId);
},

如果我做对了，shipCargoId是船的身份证？ CatValId是CatVal实体的主键。通过选择CatVal实体，您还可以选择ID，因此您无需明确地执行此操作。

使用查询构建器结果

1 个答案: