Question

实际上有一种方法可以存储n个输入的每个不同输入，然后以正确的顺序显示所有这些输入，例如：

用户输入记录编号，姓名，员工类型，为n个用户工作的天数

在n个用户之后，它会一次显示以下所有：

记录编号：1

员工姓名：Alexander

员工类型：C

工作天数：5

收费（RM）：2500.00

记录编号：2

员工姓名：贝拉

员工类型：V

工作天数：10

收费（RM）：1000.00

记录编号：3

员工姓名：Tom

员工类型：S

工作天数：20

收费（RM）：5000.00

或者只能逐个显示？这是我目前的代码

print("{0:^15s}{1:^25s}".format("Employee Type", "Employee Rate (per day)"))
print("{0:^15s}{1:>15s}".format("C", "RM 500.00"))
print("{0:^15s}{1:>15s}".format("S", "RM 250.00"))
print("{0:^15s}{1:>15s}".format("V", "RM 100.00"))
print()

numEmployee = 1
confirmation = 0

while confirmation != "Y":
    numEmployee = input("Enter The Number Of Employees To Be Keyed In: ")
    while numEmployee == str():
        print("No Input Has Been Detected. Please Input Number Of Employee(s) In An Integer")
        numEmployee = input("Enter The Number Of Employees To Be Keyed In: ")
    while eval(numEmployee) <= 0:
        print("Please Enter A Valid Number Of Employees")
        numEmployee = input("Enter The Number Of Employees To Be Keyed In: ")
    confirmation = input("Are You Sure You The Number Of Employee Is Correct? Enter Y to Continue or any other key to reenter The Correct Number:")
    confirmation = confirmation.upper()
print()

numEmployee = eval(numEmployee)

#for recordNum in range (1, numEmployee + 1):
recordNum = 1
finalTotalC = 0
finalTotalS = 0
finalTotalV = 0

while recordNum <= numEmployee:
    print("Record Number: ", recordNum)
    recordNum = recordNum + 1

    name = input("Employee Name: ")
    while name == str():
        print("Please Enter A Name")
        name = input("Employee Name: ")

    employeeType = input("Employee Type: ")
    employeeType = employeeType.upper()
    while employeeType == str():
        print("No Input Has Been Detected. Please Input An Employee Type")
        employeeType = input("Employee Type: ")
        employeeType = employeeType.upper()
    while employeeType != "C" and  employeeType != "S" and  employeeType != "V":
        print("Employee Type Is Invalid. Please Enter C,S or V Only")
        employeeType = input("Employee Type: ")
        employeeType = employeeType.upper()

    daysWorked = input("Days Worked: ")
    while daysWorked == str():
        print("No Input Has Been Detected. Please Input Number Of Days Worked In That Month")
        daysWorked = input("Days Worked: ")
    while eval(daysWorked) < 0 or eval(daysWorked) > 31:
        print("Please Enter The Number Of Days In A Range Of 0 until 31 Only")
        daysWorked = input("Days Worked: ")

    daysWorked = eval(daysWorked)

    if employeeType == "C":
        EMPLOYEERATE = 500.00
        print("Pay (RM): ", format(daysWorked*EMPLOYEERATE, ",.2f"))
        totalC = daysWorked*EMPLOYEERATE
        finalTotalC = finalTotalC + totalC
        print()

    if employeeType == "S":
        EMPLOYEERATE = 250.00
        print("Pay (RM): ", format(daysWorked*EMPLOYEERATE, ",.2f"))
        totalS = daysWorked*EMPLOYEERATE
        finalTotalS = finalTotalS + totalS
        print()

    if employeeType == "V":
        EMPLOYEERATE = 100.00
        print("Pay (RM): ", format(daysWorked*EMPLOYEERATE, ",.2f"))
        totalV = daysWorked*EMPLOYEERATE
        finalTotalV = finalTotalV + totalV
        print()

Answer 1

您需要在接收数据时将数据存储在某处。我建议一个列表（https://docs.python.org/2/tutorial/datastructures.html#more-on-lists）的dicts（https://docs.python.org/2/tutorial/datastructures.html#dictionaries）可能适合您的情况。然后，您可以在完成后迭代列表（为了打印）。

存储每个单个输入然后按顺序显示

1 个答案: