Question

我有与此类似的字符串

word1/word2/word3/<b>word3</b>

我想通过正斜杠来爆炸这个字符串。这样我就可以得到以下结果。

Array = (
[0] => 'word1',
[1] => 'word2',
[2] => 'word3',
[3] => '<b>word3</b>'
);

但我无法得到上述结果。相反，我得到以下结果

Array = (
    [0] => 'word1',
    [1] => 'word2',
    [2] => 'word3',
    [3] => '<b>word3<',
    [4] => 'b>'
    );

我应该使用什么正则表达式来使用preg_split函数来实现预期的结果？

Answer 1

使用DECLARE @email_id NVARCHAR(450)='1', @id BIGINT, @max_id BIGINT, @query NVARCHAR(1000) SELECT @id=MIN(id), @max_id=MAX(id) FROM [EmployeeInfo ] WHILE @id<=@max_id BEGIN SELECT @email_id=email_id ,@Gift =gift FROM EmployeeInfo e join PromoInfo p on p.id = e.id where ID= @id SET @body = N''+@email_id+'Your Gift Is' +@Gift; SET @body = @body EXEC msdb.dbo.sp_send_dbmail @profile_name = 'Profile_Name', @body = @body, @body_format ='HTML', @recipients = @email_id, @copy_recipients = '', @subject = 'Subject' ; SELECT @id=MIN(id) FROM [EmployeeInfo ] where id>@id END函数和特定的正则表达式模式：

preg_split

$s = 'word1/word2/word3/<b>word3</b>'; $result = preg_split('~(?<!<)/~', $s); print_r($result); - 被视为正则表达式表达式
~ - 负面后瞻断言，确保正斜杠(?<!<)/前面没有/

输出：

通过正斜杠拆分字符串但忽略字符串中的＆lt; \

1 个答案: