我正在尝试将第一个和最后一个选择器与nextUntil和prevUntil
一起包括在内JQUERY
$('.selectedDay').parent().prevUntil('li.weeks').css('background', '#F00');
$('.selectedDay').parent().nextUntil('li.weeksClose').css('background', '#F00');
答案 0 :(得分:2)
试试这个:
$('.selectedDay').parent().prevAll('.weeks').first().css('background', '#F00');
$('.selectedDay').parent().nextAll('li.weeksClose').first().css('background', '#F00');
答案 1 :(得分:1)
由于
li.weeks
前面有li.weeksClose
;和li.weeksClose
之后是li.weeks
为什么不简单地使用:
$('.selectedDay').parent().prevUntil('li.weeksClose').css('background', '#F00');
$('.selectedDay').parent().nextUntil('li.weeks').css('background', '#F00');
或者,您可以使用CSS库,例如 ax ,而不是使用 jQuery 等javascript库。
您需要使用以下两个斧头选择器:
<
选择直接父级(它与标准CSS中的>
相反)!
选择任何以前的兄弟(它与标准CSS中的~
相反)然后您可以编写以下样式规则:
.selectedDay < li ! li,
.selectedDay < li ~ li {
background-color: rgb(255, 0, 0);
}
.selectedDay < li ! li.weeks ! li,
.selectedDay < li ~ li.weeksClose ~ li {
background-color: rgb(255, 255, 255);
}
工作示例:
.selectedDay < li ! li,
.selectedDay < li ~ li {
background-color: rgb(255, 0, 0);
}
.selectedDay < li ! li.weeks ! li,
.selectedDay < li ~ li.weeksClose ~ li {
background-color: rgb(255, 255, 255);
}
&#13;
<ul class="x-axis">
<li class="td-front weeks"><span>30<br>W</span></li>
<li class="td-front"><span>31<br>W</span></li>
<li class="td-day firstFortNight1"><span>01<br> W</span></li>
<li class="td-day"><span>02<br>W</span></li>
<li class="td-day"><span >03<br>W</span></li>
<li class="td-day"><span>04<br>W</span></li>
<li class="td-day weeksClose"><span>05<br>W</span>
<p>Week Avg : 9.15</p>
</li>
<li class="td-day weeks"><span>06<br>W</span></li>
<li class="td-day"><span>07<br>W</span></li>
<li class="td-day"><span>08<br>W</span></li>
<li class="td-day"><span class="selectedDay">09<br>W</span></li>
<li class="td-day"><span>10<br>W</span></li>
<li class="td-day"><span>11<br>W</span></li>
<li class="td-day weeksClose"><span>12<br>W</span>
<p>Week Avg : 9.15</p>
</li>
<li class="td-day weeks"><span>13<br>W</span></li>
<li class="td-day"><span>14<br>W</span></li>
<li class="td-day firstFortNight15"><span>15<br> W</span></li>
<li class="td-day secondFortNight16"><span>16<br> W</span></li>
<li class="td-day"><span>17<br>W</span></li>
<li class="td-day"><span>18<br>W</span></li>
<li class="td-day weeksClose"><span>19<br>W</span>
<p>Week Avg : 9.15</p>
</li>
<li class="td-day weeks"><span>20<br>W</span></li>
<li class="td-day"><span>21</span><br>W</li>
<li class="td-day"><span>22<br>W</span></li>
<li class="td-day"><span>23<br>W</span></li>
<li class="td-day"><span>24<br>W</span></li>
<li class="td-day"><span>25<br>W</span></li>
<li class="td-day weeksClose"><span>26<br>W</span>
<p>Week Avg : 9.15</p>
</li>
<li class="td-day weeks"><span>27<br>W</span></li>
<li class="td-day"><span>28<br>W</span></li>
<li class="td-day"><span>29<br>W</span></li>
<li class="td-day"><span>30<br>W</span></li>
<li class="td-day secondFortNight30"><span>31<br> W</span></li>
<li class="td-back"><span>01<br>W</span></li>
<li class="td-back weeksClose"><span>02<br>W</span>
<p>Week Avg : 9.15</p>
</li>
</ul>
<script src="https://rouninmedia.github.io/axe/axe.js"></script>
&#13;
答案 2 :(得分:0)
完成。
$('.selectedDay').parent().prevAll('.weeks').first().css('background', '#F00');
$('.selectedDay').parent().prevUntil('.weeks').css('background', '#F00');
$('.selectedDay').parent().nextAll('li.weeksClose').first().css('background', '#F00');
$('.selectedDay').parent().nextUntil('li.weeksClose').css('background', '#F00');