我是新手,并尝试使用以下代码创建一个函数:
.sequelizerc
上述查询的结果是:
CREATE OR REPLACE FUNCTION public.get_bulan()
returns table (request_detail timestamp with time zone)
language plpgsql stable
as $function$
begin
return query
select
case
when (extract(DAY FROM now()) >= 25) then generate_series(date_trunc('year', now()), date_trunc('day', now()) ,interval '1 month')
when (select extract(month FROM now()) = 2) then now() - (interval '1' month * generate_series(0,1))
when (select extract(month FROM now()) = 1) then now() - (interval '1' month * generate_series(0,2))
else generate_series((select date(date_trunc('year', now()))), (select date(now())-'1 month'::interval), interval '1 month')
end
order by timetstamptz(request_detail) desc;
end;
$function$;
我尝试使用2017-01-01 00:00:00
2017-02-01 00:00:00
2017-03-01 00:00:00
2017-04-01 00:00:00
2017-05-01 00:00:00
2017-06-01 00:00:00
2017-07-01 00:00:00
和order by desc
,但它不起作用。我想通过降序来下订单,所以我得到2017-07-01到2017-01-01的结果。我该怎么做?
答案 0 :(得分:2)
您有两种方法可以做到这一点:
添加as result_timestamp order by result_timestamp desc;
CREATE OR REPLACE FUNCTION public.get_bulan()
returns table (request_detail timestamp with time zone)
language plpgsql stable
as $function$
begin
return query
select
case
when (extract(DAY FROM now()) >= 25) then generate_series(date_trunc('year', now()), date_trunc('day', now()) ,interval '1 month')
when (select extract(month FROM now()) = 2) then now() - (interval '1' month * generate_series(0,1))
when (select extract(month FROM now()) = 1) then now() - (interval '1' month * generate_series(0,2))
else generate_series((select date(date_trunc('year', now()))), (select date(now())-'1 month'::interval), interval '1 month')
end as result_timestamp order by result_timestamp desc;
end;
$function$;
或者,当您从其他地方调用时,您可以从过程和顺序中删除排序:
CREATE OR REPLACE FUNCTION public.get_bulan()
returns table (request_detail timestamp with time zone)
language plpgsql stable
as $function$
begin
return query
select
case
when (extract(DAY FROM now()) >= 25) then generate_series(date_trunc('year', now()), date_trunc('day', now()) ,interval '1 month')
when (select extract(month FROM now()) = 2) then now() - (interval '1' month * generate_series(0,1))
when (select extract(month FROM now()) = 1) then now() - (interval '1' month * generate_series(0,2))
else generate_series((select date(date_trunc('year', now()))), (select date(now())-'1 month'::interval), interval '1 month')
end;
end;
$function$;
并致电:
select request_detail from public.get_bulan() order by request_detail desc
注意:第二个很柔韧,你可以轻松操控。
答案 1 :(得分:1)
select
(case
when (extract(DAY FROM now()) >= 25) then generate_series(date_trunc('year', now()), date_trunc('day', now()) ,interval '1 month')
when (select extract(month FROM now()) = 2) then now() - (interval '1' month * generate_series(0,1))
when (select extract(month FROM now()) = 1) then now() - (interval '1' month * generate_series(0,2))
else generate_series((select date(date_trunc('year', now()))), (select date(now())-'1 month'::interval), interval '1 month')
end) as time_st order by time_st desc
输出:
2017-07-01 00:00:00+05:30
2017-06-01 00:00:00+05:30
2017-05-01 00:00:00+05:30
2017-04-01 00:00:00+05:30
2017-03-01 00:00:00+05:30
2017-02-01 00:00:00+05:30
2017-01-01 00:00:00+05:30
答案 2 :(得分:1)
SQL CASE
语句的第一个和最后一个分支按降序返回行,其他两个按升序返回。因此,您需要在ORDER BY
外部使用其他SELECT
。
干净的修复方法是让所有4个分支以相同的顺序返回行。
或者更确切地说,完全重写这个以解开混乱:
SELECT *
FROM generate_series(
CASE
WHEN extract(DAY FROM now()) >= 25 THEN date_trunc('month', now())
WHEN extract(MONTH FROM now()) <= 2 THEN now()
ELSE now() - interval '1 month'
END
, date_trunc('year' , now())
, interval '- 1 month' -- negative interval
) t(request_detail)
ORDER BY request_detail DESC; -- redundant
负间隔自动生成降序。您可以添加ORDER BY request_detail DESC
以使其清晰并更正标准SQL。
如果您愿意,可以将查询包装到函数中。
最重要的是, 不会 在generate_series()
语句中包含像CASE
这样的集合返回函数。这从来都不是一个好主意,但从Postgres 10开始,它会引发一个错误:
ERROR: set-returning functions are not allowed in CASE
演示:
dbfiddle here