JSON后端人员为我提供了多个父子,因此我必须将动态循环显示给父子。
JSON
"data": [
{
"id": 25,
"slug": "mobiles",
"parent_id": null,
"name": "Mobiles"
},
{
"id": 26,
"slug": "mobile-phones-accessories",
"parent_id": 25,
"name": "Mobile Phones accessories"
},
{
"id": 27,
"slug": "computer-laptop",
"parent_id": null,
"name": "Computer & Laptop"
},
{
"id": 28,
"slug": "laptops",
"parent_id": 27,
"name": "Laptops"
},
{
"id": 29,
"slug": "mobile-phones",
"parent_id": 26,
"name": "Mobiles Phone"
}
]
我的功能(请忽略这一点。这只是一次尝试,但我有一个孩子的父母)
renderCategoriesHtml() {
const { categories } = this.props;
if (!categories) return false;
const nullCat = [];
categories.map((obj) => {
if (obj.parent_id == null) {
nullCat.push(obj);
}
});
return nullCat.map(
(parentCat, i) => (
<div className="form-group" key={i}>
<div className="checkbox" key={i}>
<label>
<Field
name={`categories.${parentCat.id}`}
component="input"
type="checkbox"
/>
{parentCat.slug}
</label>
</div>
{
categories.map(
(childCat, j) => (
parentCat.id == childCat.parent_id ?
<div className="checkbox ml-20" key={j}>
<label>
<Field
name={`categories.${childCat.id}`}
component="input"
type="checkbox"
/>
{childCat.slug}
</label>
</div>
: ''
)
)
}
</div>
)
);
}
我想要这个(我想要的动态HTML)
<ul>
<li>mobiles</li>
<ul>
<li>mobile-phones-accessories</li>
<ul>
<li>mobile-phones</li>
</ul>
</ul>
<li>computer-laptop</li>
<ul>
<li>laptops</li>
</ul>
</ul>
答案 0 :(得分:2)
试试这个:
class TreeRender extends React.Component {
state = {
data: JSON.parse('[{"id": 25,"slug": "mobiles","parent_id": null,"name": "Mobiles"},{"id": 26,"slug": "mobile-phones-accessories","parent_id": 25,"name": "Mobile Phones accessories"},{"id": 27,"slug": "computer-laptop","parent_id": null,"name": "Computer & Laptop"},{"id": 28,"slug": "laptops","parent_id": 27,"name": "Laptops"},{"id": 29,"slug": "mobile-phones","parent_id": 26,"name": "Mobiles Phone"}]')
}
getCurrent = (node) => this.state.data.filter(cNode => cNode.parent_id == node).map(cNode => (
<ul key={`node_${cNode.id}`}>
<li>{cNode.name}</li>
{this.getCurrent(cNode.id)}
</ul>
))
render() {
return (
<div>
{this.getCurrent(null)}
</div>
);
}
}