Dim sql As String = "SELECT DISTINCT LED.IDX As IDX, CORPCODE, UNITTYPECODE, UPPERFORMATIONCODE, FORMATIONCODE, LED.UNITCODE As UNITCODE,LED.STORECODE As STORECODE, LED.SECTIONNO As SECTIONNO, LED.PARTNO As PARTNO, "
sql &= " LED.BATCHNO As BATCHNO, UNITITEMCATEGORYCODE, LEDGERDATE, ENTITLEMENT, HOLDING, SURPLUS, SHORTAGE, COSTHOLDING, COSTENTITLEMENT, INITIALSTOCK, EMPLOYQTY, FIGHTQTY, ITEMAGE1, ITEMAGE2, ITEMAGE3,"
sql &= " ITEMAGE4, LED.BAH_BEREK, LED.JENIS_BEREK, JPTD_NO, LASTUPDATE, LED.ITEMTYPECODE As ITEMTYPECODE, LED.TOOLTYPECODE As TOOLTYPECODE, LED.PAKAIBHGCODE, LED.PAKAICODE, ITEMNIDX, LED.CREATEID As CREATEID, "
sql &= " LED.UPDATEID As UPDATEID, LED.CREATEDATE As CREATEDATE, LED.UPDATEDATE As UPDATEDATE, "
sql &= " USERID, RANKCODE, SERVICENO, USERNAME, DESIGNATIONCODE, PASSWORD, "
sql &= " 'OPER' AS GROUPCODE,5 AS ACESSID, 0 AS STATUS "
sql &= " FROM (LEDGER AS LED) "
sql &= " LEFT JOIN NUSER On NUSER.USERID = LED.UPDATEID WHERE (1=1) "
If condation <> "" Then
sql += condation
End If
sql &= " UNION SELECT DISTINCT LED.IDX As IDX, CORPCODE, UNITTYPECODE, UPPERFORMATIONCODE, FORMATIONCODE, LED.UNITCODE As UNITCODE, LED.STORECODE As STORECODE, LED.SECTIONNO As SECTIONNO, LED.PARTNO As PARTNO, "
sql &= " LED.BATCHNO As BATCHNO, UNITITEMCATEGORYCODE, LEDGERDATE, ENTITLEMENT, HOLDING, SURPLUS, SHORTAGE, COSTHOLDING, COSTENTITLEMENT, INITIALSTOCK, EMPLOYQTY, FIGHTQTY, ITEMAGE1, ITEMAGE2, ITEMAGE3,"
sql &= " ITEMAGE4, LED.BAH_BEREK, LED.JENIS_BEREK, JPTD_NO, LASTUPDATE, LED.ITEMTYPECODE As ITEMTYPECODE, LED.TOOLTYPECODE As TOOLTYPECODE, LED.PAKAIBHGCODE, LED.PAKAICODE, ITEMNIDX, LED.CREATEID As CREATEID, "
sql &= " LED.UPDATEID As UPDATEID, LED.CREATEDATE As CREATEDATE, LED.UPDATEDATE As UPDATEDATE,"
sql &= " ('' AS USERID), ('' AS RANKCODE),('' AS SERVICENO),('' AS USERNAME),('' AS DESIGNATIONCODE), ('' AS PASSWORD), 'OPER',5 , STATUS "
sql &= " FROM LEDGER_HISTORY LED WHERE (1=1) "
错误是查询表达式中的语法错误(缺少运算符)&#39;(&#39;&#39; AS USERID)&#39;。 任何人都可以帮我解决这个问题
答案 0 :(得分:1)
错误是正确的。问题是括号。
此语法不适用于SQL:
SELECT ('' AS USERID)
但是,这是:
SELECT ('') AS USERID
或者只是:
SELECT '' AS USERID
FROM (LEDGER AS LED)
存在同样的问题。