Question

我正在构建基于firebase数据库的实时聊天应用所以我的问题是，每次应用程序调用oncreat方法时，我都会调用displaychatmessages（）方法，问题是我的数据库中的所有消息都显示在listview上。我的问题，当数据库变大时，应用程序可能会遇到一些问题？经过一些月或几年？我的意思是它会在开始时间处理很多数据

作为一种解决方案，我试图在以后存储旧邮件并稍后加载它们，应用程序只会加载新添加的子邮件？但我不知道如何开始这个，如果一个人可以帮助我一个好主意？

我的旧displayChatMessages方法： 关于新的想法？

private void displayChatMessages() {

    RecyclerView recycler = (RecyclerView)findViewById(R.id.myRv);
    LinearLayoutManager layoutmang = new LinearLayoutManager(this);
    layoutmang.setStackFromEnd(true);
    recycler.setLayoutManager(layoutmang);
    mAdapter = new FirebaseRecyclerAdapter<ChatMessage, RecyclerView.ViewHolder>(
            ChatMessage.class, R.layout.activity_main, RecyclerView.ViewHolder.class, FirebaseDatabase.getInstance().getReference()) {
        @Override
        protected void populateViewHolder(final RecyclerView.ViewHolder viewHolder, final ChatMessage user,
                                          final int position) {


            int y=0;
            ChatMessage user2;
            if (position>1){
                user2 = getItem(position - 1);
            }else{
                user2 = getItem(position );
            }

            ChatMessage ori2 = getItem(position );
            if (user.getMessageUser().matches(FirebaseAuth.getInstance().getCurrentUser().getEmail())) {
                    if (user2.getMessageFULL()<ori2.getMessageFULL()){
                    y=1;
                    populateType1((HolderMe) viewHolder, user,  1);
                }else{
                    populateType1((HolderMe) viewHolder, user, 0);
                }

            }else if (!user.getMessageUser().matches(FirebaseAuth.getInstance().getCurrentUser().getEmail())){
               if (user2.getMessageFULL()<ori2.getMessageFULL()){
                    populateType2((HolderYou) viewHolder, user, 1,FirebaseAuth.getInstance().getCurrentUser().getEmail());
                }else{
                    populateType2((HolderYou) viewHolder, user, 0,FirebaseAuth.getInstance().getCurrentUser().getEmail());
                }

            }
            if(user.getMessageTime()< new Date().getTime()) {
                HolderDate vh3 = (HolderDate) viewHolder;
                populateType3(vh3, user, position);
            }
        }

            @Override
        public RecyclerView.ViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
            Log.e("ViewT",viewType+"");
            if (viewType == 1) {
                 View userType1 = LayoutInflater.from(parent.getContext())
                        .inflate(R.layout.layout_holder_me, parent, false);
                return new HolderMe(userType1);
            } else{
               View userType2 = LayoutInflater.from(parent.getContext())
                        .inflate(R.layout.layout_holder_you, parent, false);
                return new HolderYou(userType2);
            }

        }

        @Override
        public int getItemViewType(int position) {
              ChatMessage user = getItem(position);
            String s = FirebaseAuth.getInstance().getCurrentUser().getEmail();
            if (s.equals(user.getMessageUser())) {
             return 1;
            } else {
                 return 2;
            }

        }

        private void populateType1(HolderMe v, ChatMessage model, int position) {
            v.getTimeView().setText(DateFormat.format("HH:mm",model.getMessageTime()));
            if (position==1) {
                v.getFullDateView().setText(DateFormat.format("dd-MM-yyyy", model.getMessageTime()));
                v.getFullDateView().setVisibility(View.VISIBLE);
            }
                v.getTextv().setText(model.getMessageText());
        }
        private void populateType3(HolderDate vcv, ChatMessage model, int position) {
            vcv.getDate().setText(DateFormat.format("dd-MM-yyyy",model.getMessageTime()));
        }
        private void toaa1( String text) {
            Toast.makeText(ChatActivity.this,text,Toast.LENGTH_LONG).show();
        }
        private void  populateType2(HolderYou vv, ChatMessage model, int position,String username) {
            vv.getTimeView().setText(DateFormat.format("HH:mm",model.getMessageTime()));
            if (position==1) {
                vv.getFullDateView().setVisibility(View.VISIBLE);
                vv.getFullDateView().setText(DateFormat.format("dd-MM-yyyy", model.getMessageTime()));
            }
            vv.getTextv().setText(model.getMessageText());
           if (username.matches("test2@test2.com")) {
                vv.getImageView().setBackgroundResource(R.drawable.userm);
            } else {
                vv.getImageView().setBackgroundResource(R.drawable.usera);
                }
        }

    };
    recycler.setAdapter(mAdapter);
}

Answer 1

显示聊天应用中的所有消息确实会随着消息数量的增加而出现问题。相反，您可以使用Firebase数据库查询仅显示最新消息。例如：

DatabaseReference messages = FirebaseDatabase.getInstance().getReference();
Query recent = messages.orderByKey().limitToLast(100);

然后在适配器中使用它：

mAdapter = new FirebaseRecyclerAdapter<ChatMessage, RecyclerView.ViewHolder>(
        ChatMessage.class, 
        R.layout.activity_main,
        RecyclerView.ViewHolder.class, 
        recent) {

Android - 使用Firebase的实时聊天应用程序

1 个答案: