我正在尝试在python中创建多线程Web服务器,但请求是逐个处理的。搜索了几个小时后,我发现了这个link,但批准的答案似乎不正确,因为那里的请求也是逐个处理的。 这是代码:
from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler
from SocketServer import ThreadingMixIn
import threading
from time import sleep
class Handler(BaseHTTPRequestHandler):
def do_GET(self):
self.send_response(200)
self.end_headers()
sleep(5)
message = threading.currentThread().getName()
self.wfile.write(message)
self.wfile.write('\n')
return
class ThreadedHTTPServer(ThreadingMixIn, HTTPServer):
"""Handle requests in a separate thread."""
if __name__ == '__main__':
server = ThreadedHTTPServer(('localhost', 8080), Handler)
print 'Starting server, use <Ctrl-C> to stop'
server.serve_forever()
我添加了“sleep(5)”5秒延迟来处理请求。之后我发送了多个请求,但所有请求都是逐个处理的,每个请求花了5秒钟。我无法找到原因。帮助我。
答案 0 :(得分:0)
这里的关键要求是能够在send_response
和返回的数据之间有5秒的延迟。这意味着你需要流媒体;您无法使用ThreadingMixIn
,gunicorn
或任何其他此类黑客攻击。
你需要这样的东西:
import time, socket, threading
sock = socket.socket (socket.AF_INET, socket.SOCK_STREAM)
host = socket.gethostname()
port = 8000
sock.bind((host, port))
sock.listen(1)
HTTP = "HTTP/1.1 200 OK\nContent-Type: text/html; charset=UTF-8\n\n"
class Listener(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self.daemon = True # stop Python from biting ctrl-C
self.start()
def run(self):
conn, addr = sock.accept()
conn.send(HTTP)
# serve up an infinite stream
i = 0
while True:
conn.send("%i " % i)
time.sleep(0.1)
i += 1
[Listener() for i in range(100)]
time.sleep(9e9)