Question

我找不到Vine的API来获取页面内容的标题，描述和图像。 JSON位于脚本标记中的页面主体中：。如何使用PHP获取此脚本标记的内容（JSON），以便对其进行解析？

Vine页面：

https://vine.co/v/igO3EbIXDlI

来自页面来源

<script type="application/ld+json">
            {
              "@context": "http://schema.org",
              "@type": "SocialMediaPosting",
              "url": "https://vine.co/v/igO3EbIXDlI",
              "datePublished": "2016-03-01T00:58:35",
              "author": {
                "@type": "Person",
                "name": "MotorAddicts\u2122",
                "image": "https://v.cdn.vine.co/r/avatars/39FEFED72B1242718633613316096_pic-r-1439261422661708f3e9755.jpg.jpg?versionId=LPjQUQ4KmTIPLu3iDbXw4FipgjEpC6fw",
                "url": "https://vine.co/u/989736283540746240"
              },
              "articleBody": "Mmm...  Black black blaaaaack!! \ud83d\ude0d ( Drift \u53d1 )",
              "image": "https://v.cdn.vine.co/r/videos/98C3799A811316254965085667328_SW_WEBM_14567938452154dc600dbde.webm.jpg?versionId=wPuaQvDxnpwF7KjSGao21hoddooc3eCl",
              "interactionCount": [{
                "@type": "UserInteraction",
                "userInteractionType": "http://schema.org/UserLikes",
                "value": "1382"
              }, {
                "@type": "UserInteraction",
                "userInteractionType": "http://schema.org/UserShares",
                "value": "368"
              }, {
                "@type": "UserInteraction",
                "userInteractionType": "http://schema.org/UserComments",
                "value": "41"
              }, {
                "@type": "UserInteraction",
                "userInteractionType": "http://schema.org/UserViews",
                "value": "80575"
              }],

              "sharedContent": {
                "@type": "VideoObject",
                "name" : "Mmm...  Black black blaaaaack!! \ud83d\ude0d ( Drift \u53d1 )",
                "description" : "",
                "thumbnailUrl" : "https://v.cdn.vine.co/r/videos/98C3799A811316254965085667328_SW_WEBM_14567938452154dc600dbde.webm.jpg?versionId=wPuaQvDxnpwF7KjSGao21hoddooc3eCl",
                "uploadDate" : "2016-03-01T00:58:35",
                "contentUrl" : "https://v.cdn.vine.co/r/videos_h264high/98C3799A811316254965085667328_SW_WEBM_14567938452154dc600dbde.mp4?versionId=w7ugLPYtj5LWeVUsXaH1bt2VuK8QE0qv",
                "embedUrl" : "https://vine.co/v/igO3EbIXDlI/embed/simple",
                "interactionCount" : "82366"
              }
            }
          </script>

此后该怎么办？

$html = 'https://vine.co/v/igO3EbIXDlI';
$dom = new DOMDocument;
$dom->loadHTML($html);

Answer 1

当我转到该页面时，我看不到您要引用的脚本标记。所以我找到了一个有一个的页面，这就是我要做的：

[1,2,3]

如何从<scriptscript type =“application / ld + json”>获取内容json

1 个答案: