Question

当我尝试从字典创建json时，我得到一个错误的格式用分号而不是用于json的逗号

let jsonData = try? JSONSerialization.data(withJSONObject: params)

params是字典。我尝试使用选项：.prettyPrinted但相同

result 
{
   "key": "value";
   "key": "value"
}
instead of 
{
   "key": "value",
   "key": "value"
}

我试图从一个文件中读取但是用分号读取相同的结果:(

更新这是完整的代码：

let params: Dictionary<String, String> = ["country":"A"
    ,"language":"A"
    ,"query":"some query"
    ,"context": "null"]
let baseURL = "someURL"
let url = URL(string: baseURL)!
var request = URLRequest(url: url)
request.httpMethod = "POST"
do {
    request.httpBody = try JSONSerialization.data(withJSONObject: params, options: .prettyPrinted)
    print(try? JSONSerialization.jsonObject(with: request.httpBody!))

} catch let error {
    print(error.localizedDescription)
}

这是输出：

Optional({
    context = null;
    country = A;
    language = A;
    query = "some query";
})

可选不是问题，而是分号

let json = try! JSONSerialization.jsonObject(with: request.httpBody!, options: .allowFragments)

输出：

{
    context = null;
    country = A;
    language = A;
    query = "some query";
}

Answer 1

这条线解决了我的问题：

request.addValue("application/json", forHTTPHeaderField: "Content-Type")

Answer 2

let dic = ["2": "B", "1": "A", "3": "C"]


        do {
            //Convert to Data
            let jsonData = try JSONSerialization.data(withJSONObject: dic, options: JSONSerialization.WritingOptions.prettyPrinted)

            //Convert back to string. Usually only do this for debugging
            // just get Json string
            if let JSONString = String(data: jsonData, encoding: String.Encoding.utf8) {
                print(JSONString)
            }
        } catch {
            print(error.localizedDescription)
        }

错误的json格式为htmlBody swift

2 个答案: