使用puppeteer,您如何以编程方式提交表单?到目前为止,如果表单实际包含提交输入,我已经能够使用page.click('.input[type="submit"]')
执行此操作。但是对于不包含提交输入的表单,关注表单文本输入元素并使用page.press('Enter')
似乎并不会导致表单提交:
const puppeteer = require('puppeteer');
(async() => {
const browser = await puppeteer.launch();
const page = await browser.newPage();
await page.goto('https://stackoverflow.com/', {waitUntil: 'load'});
console.log(page.url());
// Type our query into the search bar
await page.focus('.js-search-field');
await page.type('puppeteer');
// Submit form
await page.press('Enter');
// Wait for search results page to load
await page.waitForNavigation({waitUntil: 'load'});
console.log('FOUND!', page.url());
// Extract the results from the page
const links = await page.evaluate(() => {
const anchors = Array.from(document.querySelectorAll('.result-link a'));
return anchors.map(anchor => anchor.textContent);
});
console.log(links.join('\n'));
browser.close();
})();
答案 0 :(得分:22)
试试这个
SELECT ... FROM b WHERE a_id IN (the list you just got)
SELECT ... FROM c WHERE a_id IN (the list you just got)
对于v0.11.0和laters:
const form = await page.$('form-selector');
await form.evaluate(form => form.submit());
答案 1 :(得分:15)
如果您尝试填写并提交登录表单,则可以使用以下内容:
await page.goto('https://www.example.com/login');
await page.type('#username', 'username');
await page.type('#password', 'password');
await page.click('#submit');
await page.waitForNavigation();
console.log('New Page URL:', page.url());