Question

我目前拥有从客户端获取http帖子的Ruby代码。它创建了另一个http帖子，我想根据帖子的响应发送一个json响应。我该怎么做呢？我想尝试使用这篇文章中的答案：How to send simple json response in Rails?

但是当我尝试编译时，它给了我错误。

require 'sinatra'
require 'rest-client'
require 'sequel'
require 'pg'
require 'json/ext'

require 'net/http'
require 'json'

require 'monza'
require 'time'

post '/receiptValidation' do
  # Find devices with the corresponding reg_tokens
  base64ReceiptDataString = params[:base64ReceiptDataString]


  uri = URI("https://sandbox.itunes.apple.com") 
    Net::HTTP.start(uri.host, uri.port, :use_ssl => uri.scheme == 
    'https') do |http|
      response = http.post('/verifyReceipt', params_json)
      parsedJson = JSON.parse(response.body)

      # ***** send JSON response here *******
      respond_to do |format|
      # ... other formats here ...
        format.jsonr do
          render :json => { 
            :status => :ok, 
            :message => "Success!",
            :html => "...insert html..."
          }.to_json
        end        
      end
  end
end

这是我得到的错误：

2017-08-20 02:36:04 - NoMethodError - undefined method `respond_to' for #<Sinatra::Application:0x007f0dcb04ba70>
2017-08-20T02:36:04.949145+00:00 app[web.1]: Did you mean?  respond_to?:
2017-08-20T02:36:04.949146+00:00 app[web.1]:    firebasepushserver.rb:315:in `block in <main>'

我希望在以下快速代码中获得响应：

        let task = URLSession.shared.dataTask(with: request) { data, response, error in
            guard let data = data, error == nil else {
                // check for fundamental networking error
                print("error=\(error)")
                return
            }

            if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {
                // check for http errors
                print("statusCode should be 200, but is \(httpStatus.statusCode)")
                print("response = \(response)")
            }

            let responseString = String(data: data, encoding: .utf8)
            print("responseString = \(responseString)")

            print("done")
        }
        task.resume()

Answer 1

您可以更改

respond_to do |format|
  # ... other formats here ...
  format.jsonr do
    render :json => {
        :status => :ok,
        :message => "Success!",
        :html => "...insert html..."
    }.to_json
  end
end

到

  content_type :json
  {
      :status => :ok,
      :message => "Success!",
      :html => "...insert html..."
  }.to_json

它使用content_type，您可以找到文档here。

Ruby将json响应发送到http post

1 个答案: