使用RavenDB教程中的Northwind
数据库我尝试按员工对订单进行分组,并为每位员工获取最重要的订单。
地图:
from order in docs.Orders
select new {
Employee = order.Employee,
Count = 1,
MostRecent = order.OrderedAt,
MostRecentOrderId = order.Id
}
使用不存在的MaxBy减少:
from result in results
group result by result.Employee into grp
select new {
Employee = grp.Key,
Count = grp.Sum(result => result.Count),
MostRecent = grp.Max(result => result.MostRecent),
MostRecentOrderId = grp.MaxBy(result => result.MostRecent).MostRecentOrderId,
}
减少尝试:
from result in results
group result by result.Employee into grp
let TempMostRecent = grp.Max(result => result.MostRecent)
select new {
Employee = grp.Key,
Count = grp.Sum(result => result.Count),
MostRecent = TempMostRecent,
MostRecentOrderId = grp.First(result => result.MostRecent == TempMostRecent).MostRecentOrderId
}
然而,我的减少尝试返回0结果。
另外:RavenDB会将Order.OrderetAt
视为正确的DateTime
值并正确排序吗?
答案 0 :(得分:1)
你需要像
那样做from order in docs.Orders
select new {
Employee = order.Employee,
Count = 1,
MostRecent = order.OrderedAt,
MostRecentOrderId = order.Id
}
from result in results
group result by result.Employee into grp
let maxOrder = grp.OrderByDescending(x=>x.MostRecent).First()
select new {
Employee = grp.Key,
Count = grp.Sum(result => result.Count),
MostRecent = maxOrder.MostRecent,
MostRecentOrderId = maxOrder.MostRecentOrderId,
}