包含外部复合键的JPA Composite键失败

Question

在我的测试项目中，我尝试做以下工作：

@Entity
@IdClass(PersonId.class)
public class Person {
    @Id
    private String name;
    @Id
    @ManyToOne
    private Home home;


public class PersonId implements Serializable {
    private String name;
    private HomeId home;


@Entity
@IdClass(HomeId.class)
public class Home {
    @Id
    private String address;
    @Id
    private String bed;
    @OneToMany(mappedBy = "home")
    private List<Person> people = new LinkedList<>();

public class HomeId implements Serializable {
    private String address;
    private String bed;

我试图存放房屋，然后是房屋的人：

    Home home = new Home();
    home.setAddress("address");
    home.setBed("bed");
    entityManager.persist(home);
    Person person = new Person();
    person.setName("name");
    person.setHome(home);
    entityManager.persist(person);

家庭得到的保存是正确的，但当涉及到一个人时，我得到以下例外：

org.springframework.orm.jpa.JpaSystemException: No part of a composite identifier may be null; nested exception is org.hibernate.HibernateException: No part of a composite identifier may be null

我怎样才能让它发挥作用？请添加任何想法，任何赞赏！