Question

我如何添加一条消息“$ user_id已删除”或“$ user_id not found？”

  <?php

  $con=mysql_connect("localhost","root","");

  if(!$con) {
      die('could not connect:'.mysql_error());
  }

  mysql_select_db("final?orgdocs", $con);

  $user_id = $_POST["user_id"];

  $result = mysql_query("delete from account where user_id='$user_id' ");


  ?>

Answer 1

$user_id = $_POST["user_id"];

if(isset($user_id)) {
    $result = mysql_query("delete from account where user_id='$user_id' ");

    $affected_rows = mysql_affected_rows();    // how many rows deleted?

} else {
    $user_id = "";
    $result = false;
    $affected_rows = 0;
}

if($result == true && $affected_rows > 0) {
    echo "User " . $user_id . " deleted."; 
} else {
    echo "User " . $user_id . " not found.";
}

这应该有助于您入门。您可以将响应返回到您的调用页面，然后使用JQuery之类的JavaScript库在HTML中显示它。

编辑：我编辑了代码以获取受影响的行，因为删除查询可以返回true但删除0条记录。

http://www.php.net/manual/en/function.mysql-affected-rows.php

Answer 2

<?php

$con = mysql_connect("localhost", "root", "");

if (!$con) {
    die('could not connect:'  .mysql_error());
}

mysql_select_db("final?orgdocs", $con);

$user_id = (int)$_POST["user_id"];

$result = mysql_query("delete from account where user_id=$user_id");

$affected_rows = mysql_affected_rows();

if ($affected_rows) {
    echo "User ID '$user_id' deleted";
} else {
    echo "User ID '$user_id' not found";
}

?>

Answer 3

echo $ user_id +'已删除或未找到';

Answer 4

只需将其添加到最后：

return "user id " . ( $deleted ? "deleted" : "not found");

Answer 5

来自mysql_query手册页：

对于SELECT，SHOW，DESCRIBE，EXPLAIN和其他返回结果集的语句，mysql_query（）会在成功时返回资源，或者在出错时返回FALSE。

对于其他类型的SQL语句，INSERT，UPDATE，DELETE，DROP等，mysql_query（）成功时返回TRUE，错误时返回FALSE。

所以，它应该继续这样：

if ($result === TRUE) {
    echo "Account deleted.";
} else if ($result === FALSE) {
    echo "Account not found.";
}

我如何添加一条消息“$ user_id Deleted”或“$ user_id not found？”

5 个答案: