Question

这里我想比较两个json数组并删除重复项。

 $jsonArray1 = '["7.00 am To 8.00 am","1.00 pm To 2.00 pm","2.00 pm To 3.00 pm"]';
    $jsonArray2 = '["7.00 am To 8.00 am","1.00 pm To 2.00 pm","2.00 pm To 3.00 pm","10.00 am To 11.00 am"]';

Answer 1

首先使用json_decode将json字符串转换为数组和USE array_diff找到不同的值

这是代码 -

   $arr1 = json_decode($jsonArray1); 
   $arr2 = json_decode($jsonArray2); 

   $newarr = array_diff($arr2, $arr1);
   print_r($newarr);  // php array format
   json_encode($newarr); // json format

Answer 2

试试这个：

//you have to decode arrays
$json1 = json_decode( $jsonArray1, true);
$json2 = json_decode( $jsonArray2, true);

//find duplicates
$find_duplicates = array_intersect($json1, $json2);

//remove duplicates from first array 
$json1 = array_diff($json1, $find_duplicates);

///remove duplicates from second array 
$json2 = array_diff($json2, $find_duplicates);

Answer 3

使用array_intersect和array_filter函数的解决方案：

$json_str1 = '["7.00 am To 8.00 am","1.00 pm To 2.00 pm","2.00 pm To 3.00 pm"]';
$json_str2 = '["7.00 am To 8.00 am","1.00 pm To 2.00 pm","2.00 pm To 3.00 pm","10.00 am To 11.00 am"]';

list($arr1, $arr2) = [json_decode($json_str1), json_decode($json_str2)];
$common_items = array_intersect($arr2, $arr1);
$result = array_filter(array_merge($arr1, $arr2), function($v) use($common_items){
    return !in_array($v, $common_items);
});

print_r($result);

输出：

Array
(
    [6] => 10.00 am To 11.00 am
)

比较两个json数组并删除PHP中的重复项

这里我想比较两个json数组并删除重复项。

3 个答案: