Question

我有以下文件，格式如下所示。如何在cell = XX上进行第一次模式匹配，并在匹配cell=XX后编辑特定字符串。

File.txt
{cell DFT_AXA
{naming A_1 A_2 A_3 A_4 A_5 B_1 B_2 B_3 C_1 C_2 C_3 D_1 D_2 D_3 D_4 D_5 D_6
E_1 E_2 F_1 F_2 F_3 G_1 G_2 G_3 
H_1 H_2 H_3 H_4
}

输出将是：如果cell = DFX_AXA，请将G_2替换为I_1。

Answer 1

欢迎来到堆栈溢出Ginny。也请尝试以下awk命令：

awk '/}/{a=""} /cell/ && $2=="DFT_AXA"{a=1} a && sub("G_2","I_1") 1'  Input_file

EDIT1：根据OP的要求，现在添加非单一的班轮表格解决方案，但也有解释。

awk '/}/{                #### Looking for } if any line is having this character, if yes then do following.
a=""                     #### making variable a value to NULL.
}
/cell/ && $2=="DFT_AXA"{ #### searching string cell and then checking if 2nd field is DFT_AXA, if yes then do following.
a=1                      #### making variable a as 1.
}
a && sub("G_2","I_1") 1  #### checking variable a value is NOT NULL and substitute G_2 with I_1 in a line, if both conditions are true line will be edited and 1 will print the line. awk works on condition/action method. If condition is TRUE then action should be done, if NO action is given like here so default action print will happen.
'  Input_file            #### Mentioning Input_file here.

使用sed / awk在第一个匹配模式后编辑第二个匹配模式

1 个答案: