Question

在数组中，有些对象的有序存储，每个对象都有一个名称是＆＃34; group＆＃34;属性，如何按对象分组对象＆＃34; group＆＃34;属性，遇到的组值为0作为同一组，直到遇到组为其他值，最后获取字典

source = [ {'serial':'1','group':'0'}, {'serial':'2','group':'20'}, 
           {'serial':'3','group':'0'}, {'serial':'4','group':'0'}, 
           {'serial':'6','group':'33'}, {'serial':'7','group':'0'}, 
           {'serial':'8','group':'0'}, {'serial':'8','group':'18'} ]

我希望这个结果是

Result = { '20':[ 
             {'serial':'2','group':'20'}, 
             {'serial':'3','group':'0'}, 
             {'serial':'4','group':'0'} ], 
          '33':[ 
             {'serial':'6','group':'33'}, 
             {'serial':'7','group':'0'}, 
             {'serial':'8','group':'0'} ], 
          '18':[ {'serial':'8','group':'18'} ] 
        }

Answer 1

这可能会按预期工作，使用OrderedDict来保持源输入的顺序：

from collections import OrderedDict
result = OrderedDict()
group = None

for dic in source:
    if dic['group'] == '0':
        if group:
            result[group].append(dic)

    elif dic['group'] in result:
        result[dic['group']].append(dic)
    else:
        group = dic['group']
        result[dic['group']] = [dic]

>>> OrderedDict([('20',
              [{'group': '20', 'serial': '2'},
               {'group': '0', 'serial': '3'},
               {'group': '0', 'serial': '4'}]),
             ('33',
              [{'group': '33', 'serial': '6'},
               {'group': '0', 'serial': '7'},
               {'group': '0', 'serial': '8'}]),
             ('18', [{'group': '18', 'serial': '8'}])])

对数组中对象的属性进行分组

1 个答案: