Question

我的字典设置如下。如何从objectAtIndex:1获取实际键值（演员姓名）？

<plist version="1.0">
<dict>
    <key>Brad Pitt</key>
    <array>
        <string>Fight Club</string>
        <string>Seven</string>
        <string>Inglorious Basterds</string>
        <string>Babel</string>
    </array>
    <key>Meryl Streep</key>
    <array>
        <string>Adaptation</string>
        <string>The Devil Wears Prada</string>
        <string>Doubt</string>
        <string>Julie &amp; Julia</string>
    </array>
    <key>Chris Cooper</key>
    <array>
        <string>Adaptation</string>
        <string>American Beauty</string>
        <string>The Bourne Identity</string>
        <string>October Sky</string>
    </array>
</dict>
</plist>

Answer 1

蛮力：

- (NSString *)actorForFilm:(NSString *)film {
    NSDictionary * dictionary = ...; //your dictionary as read from the plist
    for (NSString * actorName in dictionary) {
        NSArray * films = [dictionary objectForKey:actorName];
        if ([films containsObject:film]) {
            return actorName;
        }
    }
    return nil;
}

如果要从字典中返回随机密钥，可以执行以下操作：

NSArray * allKeys = [dictionary allKeys];
NSString * randomKey = [allKeys objectAtIndex:(arc4random() % [allKeys count])];

Answer 2

字典不是有序的，因此objectAtIndex:类中没有NSDictionary方法。如果要将演员/电影对存储在有序列表中，则需要将它们存储在NSArray中，例如使用如下结构：

# pseudo-code: [] = array, {} = dictionary
[
    { actor: "Brad Pitt", movies: ["Fight Club", "Seven", "Babel"] },
    { actor: "Meryl Streep", movies: ["Adaptation", "Doubt"] },
    # etc...
]

Answer 3

我觉得你在找这样的东西？

NSString *actorName = [[actorsDictionary allKeys] objectAtIndex:index];

从字典对象中获取密钥？

3 个答案: