Question

我有一个数组

people = [
        { "name": "Bob Mike", "nickname": "john" , "points": 5 ) },
        { "name": "Andrea Maria", "nickname": "bob", "points": 5 )}
        { "name": "Larry Kiu", "nickname": "larry", "points": 4 ) }
    ];

我想按照这样排序

Andrea Maria - 5
Bob Mike - 5
Larry Kiu - 4

我没有进入排序方法，我找到了这个小代码，但它只对点进行排序，不包括名称字段中的ASC。

people.sort(dynamicSort('name')).sort(dynamicSort('points'));

function dynamicSort(property) {return function(a, b) {
   return (a[property] > b[property]) ? -1 : (a[property] < b[property])? 1 : 0;
}}

编辑：谢谢Erazihel

Answer 1

您可以先按点排序，然后使用localeCompare按名称排序。

var people = [
 { "name": "Bob Mike", "nickname": "john" , "points": 5 },
 { "name": "Andrea Maria", "nickname": "bob", "points": 5},
 { "name": "Larry Kiu", "nickname": "larry", "points": 4 }
];

people.sort(function(a, b) {
  return b.points - a.points || a.name.localeCompare(b.name)
})

console.log(people)

Answer 2

您可以使用localeCompare来比较两个字符串

const people = [
 { name: "Bob Mike", nickname: "john" , points: 5 },
 { name: "Andrea Maria", nickname: "bob", points: 5 },
 { name: "Larry Kiu", nickname: "larry", points: 4 }
];

people.sort(function(a, b) {
  return b.points - a.points || a.name.localeCompare(b.name)
});

console.log(people.map(a => a.name + ' - ' + a.points));

Answer 3

你想要的是这样的

＆＃13;

var people = [
 { "name": "Bob Mike", "nickname": "john" , "points": 5 },
 { "name": "Andrea Maria", "nickname": "bob", "points": 5},
 { "name": "Larry Kiu", "nickname": "larry", "points": 4 }
];

people.sort(compare('name')).sort(compare('points'));

function compare(property){
	return function(a, b){
		return a[property] <= b[property];
	}
}


console.log(people);

＆＃13;

compare函数返回一个可以处理指定属性的函数

Answer 4

通过保持用于检查对象的单个键以进行排序的函数的想法，您可以使用带有键的数组来按顺序进行排序，并使用回调构建一个新的数组，以便使用sort。

在sort callbak中，调用函数，直到结果值与truthy值不同，后者停止迭代。

function dynamicSort(key, order) {
    return function(a, b) {
        return +(order === 'ASC' || -1) * +(a[key] < b[key] && -1 || a[key] > b[key]);
    };
}

var people = [{ name: "Bob Mike", nickname: "john" , points: 5 }, { name: "Andrea Maria", nickname: "bob", points: 5 }, { name: "Larry Kiu", nickname: "larry", points: 4 }],
    sortBy = [['points', 'DESC'], ['name', 'ASC']].map(a => dynamicSort(...a));

people.sort(function (a, b) {
    var v = 0;
    sortBy.some(f => v = v || f(a, b));
    return v;
});

console.log(people);

.as-console-wrapper { max-height: 100% !important; top: 0; }

按名称和编号排序

4 个答案: