Question

我尝试在我的应用上删除SQLite数据库中的行此代码为“Where field value equal”

mydatabase.delete("potentials", "stage=?", new String[]{"Ready for Install"});

但我需要“Where field value not equal”

mydatabase.delete("potentials", "stage!=?", new String[]{"Ready for Install"});

和

 mydatabase.delete("potentials", "stage<>?", new String[]{"Ready for Install"});

我尝试了这段代码，但它不起作用

Answer 1

你应该在比较器中使用不等运算符：＆＃34; stage！=？＆＃34;或＆＃34;阶段＆lt;＆gt;？＆＃34;。

mydatabase.delete（＆＃34; potential＆＃34;，＆＃34; stage＆lt;＆gt;？＆＃34;，new String [] {＆＃34; Ready for Install＆＃34;}）;

Answer 2

尝试此功能：

public void DeletePostbyId(int id) {
        SQLiteDatabase db = this.getWritableDatabase();
        db.execSQL("DELETE FROM " + TABLE_CHECK + " WHERE " + ID + "!='" + id + "'");
        db.close();

        //db.delete(TABLE_CAT, CAT_ID + "= ?", new String[]{String.valueOf(catid)});
    }

Answer 3

您的查询没有任何问题。它可能在这里失败的原因是字母案例......试试这个

mydatabase.delete("potentials", "upper(stage) != ?", new String[]{"READY FOR INSTALL"});

另请注意upper(stage)附近的间距

SQLite删除Android中不等于“stage！=？”的所有行

3 个答案: