Question

我想将回复转换为NSDictionary。响应是ALRegistrationResponse（https://github.com/AppLozic/Applozic-Chat-iOS-Framework/blob/master/Applozic/DomainClasses/ALRegistrationResponse.m）的实现。

NSDictionary *_response = @
{
    @"message":[response message] != nil ? [response message] : [NSNull null],
    @"deviceKey":[response deviceKey] != nil ? [response deviceKey] : [NSNull null],
    @"userKey":[response userKey] != nil ? [response userKey] : [NSNull null],
    @"contactNumber":[response contactNumber] != nil ? [response contactNumber] : [NSNull null],
    @"lastSyncTime":[response lastSyncTime] != nil ? [response lastSyncTime] : [NSNull null],
    @"currentTimeStamp":[response currentTimeStamp] != nil ? [response currentTimeStamp] : [NSNull null],
    @"brokerURL":[response brokerURL] != nil ? [response brokerURL] : [NSNull null],
    @"imageLink":[response imageLink] != nil ? [response imageLink] : [NSNull null],
    @"statusMessage":[response statusMessage] != nil ? [response statusMessage] : [NSNull null],
    @"encryptionKey":[response encryptionKey] != nil ? [response encryptionKey] : [NSNull null],
    @"displayName":[response displayName] != nil ? [response displayName] : [NSNull null],
    @"notificationSoundFileName":[response notificationSoundFileName] != nil ? [response notificationSoundFileName] : [NSNull null]
};

Answer 1

至少有点清洁的是以下语法：

NSDictionary *_response = @{
    @"message": [response message] ?: [NSNull null],
    @"deviceKey": [response deviceKey] ?: [NSNull null],
    @"userKey": [response userKey] ?: [NSNull null],
    @"contactNumber": [response contactNumber] ?: [NSNull null],
    @"lastSyncTime": [response lastSyncTime] ?: [NSNull null],
    @"currentTimeStamp": [response currentTimeStamp] ?: [NSNull null],
    @"brokerURL": [response brokerURL] ?: [NSNull null],
    @"imageLink": [response imageLink] ?: [NSNull null],
    @"statusMessage": [response statusMessage] ?: [NSNull null],
    @"encryptionKey": [response encryptionKey] ?: [NSNull null],
    @"displayName": [response displayName] ?: [NSNull null],
    @"notificationSoundFileName": [response notificationSoundFileName] ?: [NSNull null]
};

Answer 2

另一种可能性是使用键作为选择器：

NSArray *keys = @[@"message", @"deviceKey", @"userKey", @"contactNumber", @"lastSyncTime", @"currentTimeStamp", @"brokerURL", @"imageLink", @"statusMessage", @"encryptionKey", @"displayName", @"notificationSoundFileName"];
NSMutableDictionary * dict = [[NSMutableDictionary alloc] init];
for (NSString *key in keys) {
    SEL selector = NSSelectorFromString(key);
    [dict setObject:[response performSelector: selector] ?: [NSNull null] forKey:key];
}

Answer 3

创建一个检查nil的函数怎么样？像这样：

try {
    JSONObject jsonObject = new JSONObject(jsonQuery);
    if (jsonObject != null){
        JSONArray restaurants = jsonObject.getJSONArray("restaurants");
        for (int i = 0; i < restaurants.length(); i++){
            JSONObject restaurant = restaurants.getJSONObject(i);
            JSONObject restaurantsJSONObject =restaurant.getJSONObject("restaurant");
            if(restaurantsJSONObject.has("name")) {
                String tempName = restaurantsJSONObject.getString("name");
                Log.d(TAG, "Restaurant name: " + tempName);
            }
        }
    }
} catch (JSONException e) {
    Log.d(TAG, "Exception catched: " + e);
    e.printStackTrace();
}

如何简化此代码（转换为NSDictionary）？

3 个答案: