Question

我想从我的表中删除4个有多个记录的4个。我该怎么办？

Ex:-
Table1
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i

我想删除每第4行。

我不想使用循环或光标。

Answer 1

Delete A from
(
Select *,Row_Number() Over(Order By Id) as RN from TableA
) A
where RN%4=0

SQL Fiddle Link

Answer 2

试试这个......

delete from table_name where (col1 % 4) = 0

Answer 3

使用WITH cte AS ( SELECT t.*, ROW_NUMBER() OVER (ORDER BY t.rowfield) AS rank FROM Table1 t) SELECT rowfield, fielda FROM cte WHERE rank%4 != 0。

rowfield fielda
1        a
2        b
3        c
5        e
6        f
7        g
9        i

输出

DELETE FROM

SQL小提琴：https://github.com/mperham/sidekiq/blob/master/lib/sidekiq/extensions/action_mailer.rb

如果您对输出感到满意，请使用{{1}}。

Answer 4

试试这个

DECLARE @nvalToDelete varchar(100)='4,7,3,8,9'-- just give values to delete from table 

DECLARE @temp TABLE 
  ( 
     valtodelete VARCHAR(100) 
  ) 
DECLARE @Deletetemp TABLE 
  ( 
     valtodelete INT 
  ) 

INSERT INTO @temp 
SELECT @nvalToDelete 

INSERT INTO @Deletetemp 
SELECT split.a.value('.', 'VARCHAR(1000)') AS valToDelete 
FROM   (SELECT Cast('<S>' + Replace(valtodelete, ',', '</S><S>') 
                    + '</S>' AS XML) AS valToDelete 
        FROM   @temp) AS A 
       CROSS apply valtodelete.nodes('/S') AS Split(a) 


DECLARE @Table1 TABLE 
(
ID INT,
val varchar(10)
)
INSERT INTO @Table1
SELECT 1,'a' UNION ALL
SELECT 2,'b' UNION ALL
SELECT 3,'c' UNION ALL
SELECT 4,'d' UNION ALL
SELECT 5,'e' UNION ALL
SELECT 6,'f' UNION ALL
SELECT 7,'g' UNION ALL
SELECT 8,'h' UNION ALL
SELECT 9,'i' 

SELECT * 
FROM   @Table1; 

WITH cte 
     AS (SELECT *, 
                RN = Row_number() 
                       OVER ( 
                         ORDER BY id ) 
         FROM   @Table1) 
DELETE FROM @Table1 
WHERE  id IN(SELECT id  FROM   cte 
             WHERE  rn IN (SELECT CASt(valToDelete AS INT) FROM @Deletetemp) 
)
SELECT * 
FROM   @Table1

Answer 5

这可以使用索引（如果存在）并使用numbers table

;with cte
as
(select n from numbers
where n%4=0
)
delete t
from table1 t
join
cte c
on c.n=t.id

我可以从SQL中的表中删除单个查询中的多个第n行吗？

5 个答案: