Question

我有一个XML博客Feed，我正在Wordpress上显示。以下是XML节点的简单表示：

<item>
    <title>
      Some title
    </title>
    <description>
      Some description
    </description>
    <category>
      category 1
    </category>
    <category>
      category 2
    </category>
    <category>
      category 3
    </category>
 </item>

所以你会注意到上面的类别节点显示3次，但总是有相同的名称。因此，当我使用下面的PHP在循环中显示XML节点时，我只能得到一个类别节点，因为其余的不是唯一的。

有谁知道我怎么能显示所有这些类别节点？

<?php
    $rss = new DOMDocument();
    $rss->load('http://blog.com/rss.xml');
    $feed = array();
    foreach ($rss->getElementsByTagName('item') as $node) {
      $item = array (
        'title' => $node->getElementsByTagName('title')->item(0)->nodeValue,
        'desc' => $node->getElementsByTagName('description')->item(0)->nodeValue,
        'category' => $node->getElementsByTagName('category')->item(0)->nodeValue,
        );
      array_push($feed, $item);
    }
  ?>

<?php
  $limit = 3;
  for($x=0;$x<$limit;$x++) {
  $title = str_replace(' & ', ' &amp; ', $feed[$x]['title']);
  $description = $feed[$x]['desc'];
  $category = $feed[$x]['category'];

  echo $title;
  echo $desc;
  echo $category;
  }
?>

Answer 1

为每个项目保存类别而不是一个类别：

<?php

function domNodeList2Array($node_list)
{
    $nodes = [];
    foreach ($node_list as $node) {
        $nodes[] = $node;
    }
    return $nodes;
}

$rss = new DOMDocument();
$rss->load('rss.xml');
$feed = array();
foreach ($rss->getElementsByTagName('item') as $node) {
    $item = [
        'title' => $node->getElementsByTagName('title')->item(0)->nodeValue,
        'desc' => $node->getElementsByTagName('description')->item(0)->nodeValue,
        'categories' => array_map(function ($item) {
            return $item->nodeValue;
        }, domNodeList2Array($node->getElementsByTagName('category')))];
    array_push($feed, $item);
}


$limit = 1;
for ($x = 0; $x < $limit; $x++) {
    $title = str_replace(' & ', ' &amp; ', $feed[$x]['title']);
    $description = $feed[$x]['desc'];
    $categories = $feed[$x]['categories'];

    echo $title;
    echo $description;
    foreach ($categories as $category) {
        echo $category;
    }
}

Answer 2

由于您始终采用第一个元素（使用[0]），因此总是选择第一个类别。如果您只是添加foreach，则可以将它们全部添加...

$rss = new DOMDocument ();
$rss->load ( 'rss.xml' );
$feed = array ();
foreach ( $rss->getElementsByTagName ( 'item' ) as $node ) {
    $item = array (
            'title' => $node->getElementsByTagName ( 'title' )->item ( 0 )->nodeValue,
            'desc' => $node->getElementsByTagName ( 'description' )->item ( 0 )->nodeValue,
            'category' => array());
    foreach ( $node->getElementsByTagName ( 'category' ) as $cat ) {
        $item['category'][] = $cat->nodeValue;
    }
    array_push ( $feed, $item );
}

foreach($feed as $feedItem ) {
    $title = str_replace ( ' & ', ' &amp; ', $feedItem ['title'] );
    $description = $feedItem ['desc'];
    $category = $feedItem ['category'];

    echo $title;
    echo $description;
    foreach ( $category as $cat )   {
        echo "Category:".$cat.PHP_EOL;
    }
}

Answer 3

你可以使用＆＃34; simplexml_load_file＆＃34;返回一个数组。

$xml = simplexml_load_file('http://blog.com/rss.xml');

$results = $xml->xpath('//category');

var_dump($results);

如何显示具有相同名称的XML节点？

3 个答案: