Question

children: [
      {
          o kind: "t3"
            data: {                 // ExampleNodeT3 class should be used for kind == t3
                + t3var1: "val1"
                + t3var2: true
            }
      }
      {
          o kind: "t4"                
            data: {                 // ExampleNodeT4 class should be used for kind == t4
                + t4var1: false
                + t4var2: 2346
            }
      }
] ... etc.


@JsonTypeInfo(use=Id.NAME, property="kind")
@JsonSubTypes({
@Type(value=ExampleNodeT3.class, name="t3"),
@Type(value=ExampleNodeT4.class, name="t4")})
public abstract class ExampleNode {
...
public void setData(ExampleNode data) {
    this.data = data;
}

当尝试使用Jackson反序列化时，JsonTypeInfo提示在创建ExampleNode数据时失败，因为“kind”属性与其父级关联且不可见。我尝试了各种工厂方法和Jackson注释，但由于Jackson创建了ExampleNode对象并将其传递给setData（）本身，我看不到控制创建对象类的地方。

Answer 1

从谷歌到这里，找到了解决方案。实际上这些天可能由于include = JsonTypeInfo.As.EXTERNAL_PROPERTY，例如：

 public class Parent {

    @JsonProperty("type")
    public String type;

    @JsonProperty("data")
    @JsonInclude(Include.NON_NULL)
    public ChildBase ChildBase;

    public Parent() {
        medias = new HashMap<>();
    }

    @JsonTypeInfo(use=JsonTypeInfo.Id.CLASS, include=JsonTypeInfo.As.EXTERNAL_PROPERTY, property="type")
    @JsonTypeIdResolver(ChildBaseByParentTypeResolver.class)
    public void setChildBase(ChildBase ChildBase){
        this.ChildBase = ChildBase;
    }
}


@JsonInclude(JsonInclude.Include.NON_NULL)
@JsonIgnoreProperties(ignoreUnknown = true)
public class ChildBase {
      public String someStr;

}


@JsonInclude(JsonInclude.Include.NON_NULL)
@JsonIgnoreProperties(ignoreUnknown = true)
public class AggressiveChild extends ChildBase{
     public String someStr1;

}

@JsonInclude(JsonInclude.Include.NON_NULL)
@JsonIgnoreProperties(ignoreUnknown = true)
public class ChilledChild extends ChildBase{
     public String someStr1;

}


public class ChildBaseByParentTypeResolver extends TypeIdResolverBase {

    private JavaType superType;

    @Override
    public void init(JavaType baseType) {
        superType = baseType;
    }   

    @Override
    public Id getMechanism() {
        return Id.NAME;
    }

    @Override
    public JavaType typeFromId(DatabindContext context, String id) {
        Class<?> subType = ChildBase.class;     
        switch (id) {
        case "agressiveParent":        
            subType = AggressiveChild.class;
            break;
        case "chilledParent":        
            subType = ChilledChild.class;
            break;        
        }
        return context.constructSpecializedType(superType, subType);        
    }

    @Override
    public JavaType typeFromId(String directiveType) {
         throw new NotImplementedException();
    }

}

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3 个答案: