Question

有人可以在Laravel中将此PHP代码转换为类似的内容。

$result = mysqli_query($conn, "SELECT birthday, count(*) FROM person group by birthday;");
  while ($row = mysqli_fetch_array($result, MYSQL_NUM)) {
      $yearvalues[$row[0]] = (int)$row[1];
  }

像这样：

$female = Enroll::select(DB::raw("SUM(tot_enroll) as count"))
            ->orderBy(DB::raw('sy'))
            ->groupBy(DB::raw("(sy)"))
            ->where('gender','=', 'Female')
            ->get()->toArray();
            $female = array_column($female, 'count');

Answer 1

这很简单，

您可以将您的sql查询转换为laravel中的查询构建器，如下所示：

DB::table('person')->select('birthday',DB::raw('COUNT(*) as count'))
                   ->groupBy('birthday')
                   ->get();

在您的情况下，您忘记选择sy和gender，因此orderBy，groupBy和where不执行任何操作，请尝试使用此代码获取数据

DB::table('enrollments')->select(DB::raw('sy','gender','SUM(tot_enroll) as count'))
                   ->where('gender','=', 'Female')
                   ->groupBy('sy')
                   ->orderBy('sy')
                   ->get();
                   ->toArray();

Answer 2

我假设您的型号名称是User。然后你可以这样写。

User::select('birthday')->groupBy('person')->get()->count;

在控制器中将PHP查询转换为Laravel

2 个答案: