Question

使用 TIMEDIFF 和 ADDTIME 时，查询的特定部分出现问题：

我想得到这样的结果：

| waktuhilang |
|-------------|
|    04:00:00 |
|    03:00:00 |

SELECT
ADDTIME(
    (
        SELECT
            SEC_TO_TIME(
                SUM(
                    TIME_TO_SEC(
                        maketime(
                            durasi + 0,
                            substring_index(durasi, 'Jam ', - 1) + 0,
                            0
                        )
                    )
                )
            ) waktudw
        FROM
            trans_lhpdtdw
    ),
    (
        SELECT
            TIMEDIFF(JamMasuk, JamMulai) lamaistirahat
        FROM
            trans_lhphd
    )
) waktuhilang

我看到有些人提到在子查询中使用IN代替=，但我似乎无法让它工作。有什么想法吗？感谢

我有两张桌子：

Table trans_lhpdtdw Table trans_lhphd

CREATE TABLE `trans_lhpdtdw` (
  `IdBukti` int(11) NOT NULL,
  `PartID` varchar(50) NOT NULL,
  `TypeDowntime` varchar(50) NOT NULL,
  `Durasi` varchar(50) NOT NULL,
  `KeteranganDowntime` longtext NOT NULL
 ) ENGINE=InnoDB DEFAULT CHARSET=latin1;

-- ----------------------------
-- Records of trans_lhpdtdw
-- ----------------------------
INSERT INTO `trans_lhpdtdw` VALUES ('2', 'BLAP-FG150-KT-KGX', 'SETTING MOLD', '1 Jam 0 Menit', 'ass');
INSERT INTO `trans_lhpdtdw` VALUES ('1', 'BLAP-FG152-PF-KGX', 'TIDAK ADA FASILITAS', '1 Jam 0 Menit', 'as');
INSERT INTO `trans_lhpdtdw` VALUES ('1', 'AWDX-FG002-HN-KGX', 'TIDAK ADA JOB', '2 Jam 0 Menit', 'sasa');

CREATE TABLE `trans_lhphd` (
  `IdBukti` int(11) NOT NULL AUTO_INCREMENT,
  `NoBukti` varchar(1000) NOT NULL,
  `Periode` int(6) NOT NULL,
  `Tanggal` date NOT NULL,
  `Divisi` varchar(50) NOT NULL,
  `JamKerja` varchar(10) NOT NULL,
  `JamProduksi` time NOT NULL,
  `JamSelesai` time NOT NULL,
  `JamMulai` time NOT NULL,
  `JamMasuk` time NOT NULL,
  `IdMesin` varchar(50) NOT NULL,
  `LineID` varchar(50) NOT NULL,
  `Operator` int(5) NOT NULL,
  `Planning` decimal(18,0) NOT NULL,
  `Tambahan` varchar(50) DEFAULT NULL,
  PRIMARY KEY (`IdBukti`),
  KEY `IdBukti` (`IdBukti`),
  KEY `IdBukti_2` (`IdBukti`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1;

-- ----------------------------
-- Records of trans_lhphd
-- ----------------------------
INSERT INTO `trans_lhphd` VALUES ('1', 'LHP/201708/00001', '201708', '2017-08-24', 'ALL DIVISI IMPORT (NON PPIC)', 'Shift I', '01:05:00', '09:05:00', '01:00:00', '02:00:00', 'BH 260K', 'L3002', '1', '213', '1 Jam 15 Menit');
INSERT INTO `trans_lhphd` VALUES ('2', 'LHP/201708/00002', '201708', '2017-08-17', 'INJECTION', 'Shift I', '07:00:00', '16:00:00', '11:25:00', '13:25:00', 'BH 260K', 'L2002', '100', '1000', '');

Answer 1

你的问题是第二个子查询。我猜你想要：

SELECT ADDTIME( (SELECT SEC_TO_TIME(SUM(TIME_TO_SEC(maketime(durasi + 0,
                                                  substring_index(durasi, 'Jam ', - 1) + 0, 0
                                                            )
                                                   )
                                       )
                                   )
                 FROM trans_lhpdtdw
                ),
                TIMEDIFF(JamMasuk, JamMulai)
              ) as waktuhilang
FROM trans_lhphd;

Answer 2

假设您只想查询返回的一个值，请调整第二个子查询以返回TIMEDIFF计算的SUM。

另请参阅此SQL Fiddle

查询1 ：

SELECT
 ADDTIME(
         (
           SELECT SEC_TO_TIME(SUM(TIME_TO_SEC(maketime(durasi + 0, substring_index(durasi, 'Jam ', - 1) + 0, 0)))) waktudw
           FROM trans_lhpdtdw
         )
        , (
           SELECT SUM(TIMEDIFF(JamMasuk, JamMulai)) 
           FROM trans_lhphd
         )
       ) waktuhilang

<强> Results ：

| waktuhilang |
|-------------|
|    07:00:00 |

Answer 3

为每个IdBukti

提供一行的方法

<强>查询：

SELECT
   d.IdBukti, ADDTIME(w.waktudw, TIMEDIFF(d.JamMasuk, d.JamMulai)) waktuhilang
FROM trans_lhphd as d
INNER JOIN (
           SELECT IdBukti, SEC_TO_TIME(SUM(TIME_TO_SEC(maketime(durasi + 0, substring_index(durasi, 'Jam ', - 1) + 0, 0)))) waktudw
           FROM trans_lhpdtdw
           GROUP BY IdBukti
           ) as w ON d.IdBukti = w.IdBukti

<强> Results ：

| IdBukti | waktuhilang |
|---------|-------------|
|       1 |    04:00:00 |
|       2 |    03:00:00 |

TIMEDIFF子查询在mariadb中返回超过1行

3 个答案: