Question

我有三张桌子， 1. ct_product 2. stock_in 3. stock_out

表结构和数据可用here

我想要的输出是

enter image description here

但我的查询输出是

enter image description here

请问我怎么能得到我想要的输出？

SQL查询在

之下

SELECT 
 (select product_name from ct_product where id=stock_in.ct_prod_id) as name,
 stockin.ct_prod_status,
 stockin.ct_prod_catgry,
 IFNull(stockin.stock_in, 0) stock_in,
 IFNull(stockout.stock_out, 0) stock_out,
 IFNull(stockin.stock_in, 0)-IFNull(stockout.stock_out, 0) stockinhand
FROM stock_in
LEFT JOIN
(
 SELECT 
   SUM(quantity) stock_in,
  ct_prod_id,
   ct_prod_catgry,
   ct_prod_status
  FROM stock_in
  group by ct_prod_catgry, ct_prod_id, ct_prod_status
  ) stockin ON stockin.ct_prod_id = stock_in.ct_prod_id 
  LEFT JOIN 
 (
  SELECT 
  SUM(quantity) stock_out,
   ct_prod_id,
    ct_prod_catgry,
    ct_prod_status
     FROM stock_out
     group by ct_prod_catgry, ct_prod_id, ct_prod_status 
   ) stockout ON stockout.ct_prod_id = stock_in.ct_prod_id 
  where stockout.ct_prod_catgry=stock_in.ct_prod_catgry and 
   stockout.ct_prod_status=stock_in.ct_prod_status

Answer 1

您需要在整个查询中添加一个组，并将SUM添加到总计的项目中：

SELECT 
 (select product_name from ct_product where id=stock_in.ct_prod_id) as name,
 stockin.ct_prod_status,
 stockin.ct_prod_catgry,
 SUM(IFNull(stockin.stock_in, 0)) stock_in,
 SUM(IFNull(stockout.stock_out, 0)) stock_out,
 SUM(IFNull(stockin.stock_in, 0)-IFNull(stockout.stock_out, 0)) stockinhand
FROM stock_in
LEFT JOIN
(
 SELECT 
   SUM(quantity) stock_in,
  ct_prod_id,
   ct_prod_catgry,
   ct_prod_status
  FROM stock_in
  group by ct_prod_catgry, ct_prod_id, ct_prod_status
  ) stockin ON stockin.ct_prod_id = stock_in.ct_prod_id 
  LEFT JOIN 
 (
  SELECT 
  SUM(quantity) stock_out,
   ct_prod_id,
    ct_prod_catgry,
    ct_prod_status
     FROM stock_out
     group by ct_prod_catgry, ct_prod_id, ct_prod_status 
   ) stockout ON stockout.ct_prod_id = stock_in.ct_prod_id 
  where stockout.ct_prod_catgry=stock_in.ct_prod_catgry and 
   stockout.ct_prod_status=stock_in.ct_prod_status
group by name, stockin.ct_prod_status, stockin.ct_prod_catgry

Answer 2

两个问题两点考虑（POC）

缺少第一个左连接的加入条件
你需要从stock_in中区分出不同的Ct_Prod值列表。
POC！也可以加入产品而不是为每条记录运行选择。
POC！您可以在连接上使用复合条件，并避免使用更合理的where子句。

http://sqlfiddle.com/#!9/61d62e/47/0在select查询中使用获取名称 http://sqlfiddle.com/#!9/61d62e/49/0使用联接来获取名称[我是这种方法的忠实粉丝]

SELECT 
 CP.Product_Name as name,  #I like joins instead of selects at this level
 stockin.ct_prod_status,
 stockin.ct_prod_catgry,
 IFNull(stockin.stock_in, 0) stock_in,
 IFNull(stockout.stock_out, 0) stock_out,
 IFNull(stockin.stock_in, 0)-IFNull(stockout.stock_out, 0) stockinhand
FROM (select distinct ct_prod_ID, ct_prod_status, ct_prod_Catgry from stock_in) stock_in  #needed to get a distinct list of ct_** to join
INNER JOIN ct_product cp
  on stock_in.ct_prod_ID = cp.ID
LEFT JOIN (SELECT SUM(quantity) stock_in
                , ct_prod_id
                , ct_prod_catgry
                , ct_prod_status
            FROM stock_in
            GROUP BY ct_prod_catgry, ct_prod_id, ct_prod_status
           ) stockin 
   ON stockin.ct_prod_id = stock_in.ct_prod_id 
  and stockin.ct_prod_status = stock_in.ct_prod_status #Missing
  and stockin.ct_prod_catgry = stock_in.ct_prod_catgry #Missing

LEFT JOIN (SELECT SUM(quantity) stock_out
                , ct_prod_id
                , ct_prod_catgry
                , ct_prod_status
            FROM stock_out
            GROUP BY ct_prod_catgry, ct_prod_id, ct_prod_status 
           ) stockout 
   ON stockout.ct_prod_id = stock_in.ct_prod_id 
  and stockout.ct_prod_catgry=stock_in.ct_prod_catgry #no where just and
  and stockout.ct_prod_status=stock_in.ct_prod_status #no where just and

SQL查询结果具有重复值

2 个答案: