Question

我有一个包含两列具有datetime数据类型的表。

startDateTime             | endDateTime
-----------------------------------------------------
2016/01/01 13:10:50.000   |2016/03/01 15:20:21.222

我试图从startDateTime到endDateTime从10：00：00.000到16：59：59.999范围内传递的总小数中检索上表中的输出。但它没有奏效。

Answer 1

如果startDateTime和endDateTime都必须包含而不考虑日期，那么您只需要检查时间部分。

SELECT *
FROM Table
WHERE 
   cast(startDateTime as Time) between '10:00:00.000' and '16:59:59.999'
   and
   cast(endDateTime as Time) between '10:00:00.000' and '16:59:59.999'

如果只有startDateTime 或 endDateTime需要落在该范围内，那么您可以使用or

SELECT *
FROM Table
WHERE 
   cast(startDateTime as Time) between '10:00:00.000' and '16:59:59.999'
   and
   cast(endDateTime as Time) between '10:00:00.000' and '16:59:59.999'

Answer 2

这听起来像是有限制的聚合。如果SQL Server具有greatest() / least()函数，那就太好了。但是，唉，没有。所以：

select sum(datediff(hour,
                    (case when convert(time, startDateTime) < '10:00:00' 
                          then '10:00:00'
                          when convert(time, startDateTime) > '17:00:00'
                          then '17:00:00'
                          else convert(time, startDateTime)
                     end), 
                    (case when convert(time, endDateTime) < '10:00:00' 
                          then '10:00:00'
                          when convert(time, endDateTime) > '17:00:00'
                          then '17:00:00'
                          else convert(time, endDateTime)
                     end)
                    )) as diffhours

我倾向于在几分钟内完成差异，然后在最后转换为几小时：

select sum(datediff(minute,
                    (case when convert(time, startDateTime) < '10:00:00' 
                          then '10:00:00'
                          when convert(time, startDateTime) > '17:00:00'
                          then '17:00:00'
                          else convert(time, startDateTime)
                     end), 
                    (case when convert(time, endDateTime) < '10:00:00' 
                          then '10:00:00'
                          when convert(time, endDateTime) > '17:00:00'
                          then '17:00:00'
                          else convert(time, endDateTime)
                     end)
                    )) as diffminutes

然后，您将决定是否要将转换舍入或截断为小时。

从表中检索特定时间

2 个答案: