从一个时期计算2个时期类型？

Question

这个问题困扰了我一段时间。 几个月前，我开始了一个项目，因为这个愚蠢的问题而无法进行。

如果您看到6到21之间的时间线，则有一个白天。我的问题是我需要分别计算2个日期或小时之间的时间。例如。假设开始时间是下午5:00，结束时间是晚上22点。我如何计算这两天之间的小时数和几小时？

String enter = "2017-08-16 15:00:00";
String leave = "2017-08-17 12:00:00";
org.joda.time.format.DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss");
DateTime start = formatter.parseDateTime(enter);
DateTime end = formatter.parseDateTime(leave);
Period period = new Period(start,end);
int hours = period.toStandardHours().getHours();
System.out.println(hours);

Answer 1

此解决方案使用java.time API代替Joda时间，但如果您认为有必要，您应该能够弄清楚如何自己重写。

String enter = "2017-08-14 15:00:00";
String leave = "2017-08-17 12:00:00";

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");
LocalDateTime start = LocalDateTime.parse(enter, formatter);
LocalDateTime end = LocalDateTime.parse(leave, formatter);
Duration duration = Duration.between(start, end);

int duringDay = 0;
int duringNight = 0;

// take care of all full days
long days;
if ((days = duration.toHours() / 24L) > 0) {
    duringDay += 15 * days;
    duringNight += 9 * days;
}

// take care of the remainder
for (int i = 1; i <= duration.toHours() % 24; i++) {
    LocalDateTime ldt = start.plusHours(i);
    if (ldt.getHour() <= 6 || ldt.getHour() > 21) {
        duringNight++;
    } else {
        duringDay++;
    }
}

System.out.println("Hours during day: " + duringDay);
System.out.println("Hours during night: " + duringNight);

纳秒级精度变得有点复杂：

String enter = "2017-08-13 15:30:30";
String leave = "2017-08-17 22:00:00";

DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");
LocalDateTime start = LocalDateTime.parse(enter, formatter);
LocalDateTime end = LocalDateTime.parse(leave, formatter);

Duration duration = Duration.between(LocalDateTime.of(start.toLocalDate().plusDays(1), LocalTime.of(0, 0)), LocalDateTime.of(end.toLocalDate(), LocalTime.of(0, 0)));

Duration timeDuringDay = Duration.ofDays(0);
Duration timeDuringNight = Duration.ofDays(0);

// take care of all full days
long days;
if ((days = duration.toHours() / 24L) > 0) {
    timeDuringDay = timeDuringDay.plusHours(15 * days);
    timeDuringNight = timeDuringNight.plusHours(9 * days);
}

// take care of the first day
if (start.isBefore(LocalDateTime.of(start.toLocalDate(), LocalTime.of(6, 0)))) {
    timeDuringNight = timeDuringNight.plus(Duration.between(start, LocalDateTime.of(start.toLocalDate(), LocalTime.of(6, 0))));
    timeDuringNight = timeDuringNight.plus(Duration.ofHours(3));
    timeDuringDay = timeDuringDay.plusHours(15);
} else if (start.isAfter(LocalDateTime.of(start.toLocalDate(), LocalTime.of(21, 0)))) {
    timeDuringNight = timeDuringNight.plus(Duration.between(start, LocalDateTime.of(start.toLocalDate().plusDays(1), LocalTime.of(0, 0))));
} else {
    timeDuringDay = timeDuringDay.plus(Duration.between(start, LocalDateTime.of(start.toLocalDate(), LocalTime.of(21, 0))));
    timeDuringNight = timeDuringNight.plusHours(3);
}   

// take care of the last day
if (end.isBefore(LocalDateTime.of(end.toLocalDate(), LocalTime.of(6, 0)))) {
    timeDuringNight = timeDuringNight.plus(Duration.between(LocalDateTime.of(end.toLocalDate(), LocalTime.of(0, 0)), end));
} else if (end.isAfter(LocalDateTime.of(end.toLocalDate(), LocalTime.of(21, 0)))) {
    timeDuringNight = timeDuringNight.plusHours(6);
    timeDuringNight = timeDuringNight.plus(Duration.between(LocalDateTime.of(end.toLocalDate(), LocalTime.of(21, 0)), end));
    timeDuringDay = timeDuringDay.plusHours(15);
} else {
    timeDuringNight = timeDuringNight.plusHours(6);
    timeDuringDay = timeDuringDay.plus(Duration.between(LocalDateTime.of(end.toLocalDate(), LocalTime.of(6, 0)), end));
}

System.out.println("Time during day: " + timeDuringDay);
System.out.println("Time during night: " + timeDuringNight);

Answer 2

这是我想要的最简单的代码。

<div id="desktop" style="display:none">
    <p>This is for desktop screens</p>
</div>
<div id="mobile" style="display:none">
    <p> this is for mobile screens</p>
</div>

<script>
    var isMobile = false;
    $(document).ready(function () {
        if (/(android|bb\d+|meego).+mobile|avantgo|bada\/|blackberry|blazer|compal|elaine|fennec|hiptop|iemobile|ip(hone|od)|ipad|iris|kindle|Android|Silk|lge |maemo|midp|mmp|netfront|opera m(ob|in)i|palm( os)?|phone|p(ixi|re)\/|plucker|pocket|psp|series(4|6)0|symbian|treo|up\.(browser|link)|vodafone|wap|windows (ce|phone)|xda|xiino/i.test(navigator.userAgent)
    || /1207|6310|6590|3gso|4thp|50[1-6]i|770s|802s|a wa|abac|ac(er|oo|s\-)|ai(ko|rn)|al(av|ca|co)|amoi|an(ex|ny|yw)|aptu|ar(ch|go)|as(te|us)|attw|au(di|\-m|r |s )|avan|be(ck|ll|nq)|bi(lb|rd)|bl(ac|az)|br(e|v)w|bumb|bw\-(n|u)|c55\/|capi|ccwa|cdm\-|cell|chtm|cldc|cmd\-|co(mp|nd)|craw|da(it|ll|ng)|dbte|dc\-s|devi|dica|dmob|do(c|p)o|ds(12|\-d)|el(49|ai)|em(l2|ul)|er(ic|k0)|esl8|ez([4-7]0|os|wa|ze)|fetc|fly(\-|_)|g1 u|g560|gene|gf\-5|g\-mo|go(\.w|od)|gr(ad|un)|haie|hcit|hd\-(m|p|t)|hei\-|hi(pt|ta)|hp( i|ip)|hs\-c|ht(c(\-| |_|a|g|p|s|t)|tp)|hu(aw|tc)|i\-(20|go|ma)|i230|iac( |\-|\/)|ibro|idea|ig01|ikom|im1k|inno|ipaq|iris|ja(t|v)a|jbro|jemu|jigs|kddi|keji|kgt( |\/)|klon|kpt |kwc\-|kyo(c|k)|le(no|xi)|lg( g|\/(k|l|u)|50|54|\-[a-w])|libw|lynx|m1\-w|m3ga|m50\/|ma(te|ui|xo)|mc(01|21|ca)|m\-cr|me(rc|ri)|mi(o8|oa|ts)|mmef|mo(01|02|bi|de|do|t(\-| |o|v)|zz)|mt(50|p1|v )|mwbp|mywa|n10[0-2]|n20[2-3]|n30(0|2)|n50(0|2|5)|n7(0(0|1)|10)|ne((c|m)\-|on|tf|wf|wg|wt)|nok(6|i)|nzph|o2im|op(ti|wv)|oran|owg1|p800|pan(a|d|t)|pdxg|pg(13|\-([1-8]|c))|phil|pire|pl(ay|uc)|pn\-2|po(ck|rt|se)|prox|psio|pt\-g|qa\-a|qc(07|12|21|32|60|\-[2-7]|i\-)|qtek|r380|r600|raks|rim9|ro(ve|zo)|s55\/|sa(ge|ma|mm|ms|ny|va)|sc(01|h\-|oo|p\-)|sdk\/|se(c(\-|0|1)|47|mc|nd|ri)|sgh\-|shar|sie(\-|m)|sk\-0|sl(45|id)|sm(al|ar|b3|it|t5)|so(ft|ny)|sp(01|h\-|v\-|v )|sy(01|mb)|t2(18|50)|t6(00|10|18)|ta(gt|lk)|tcl\-|tdg\-|tel(i|m)|tim\-|t\-mo|to(pl|sh)|ts(70|m\-|m3|m5)|tx\-9|up(\.b|g1|si)|utst|v400|v750|veri|vi(rg|te)|vk(40|5[0-3]|\-v)|vm40|voda|vulc|vx(52|53|60|61|70|80|81|83|85|98)|w3c(\-| )|webc|whit|wi(g |nc|nw)|wmlb|wonu|x700|yas\-|your|zeto|zte\-/i.test(navigator.userAgent.substr(0, 4))) isMobile = true;
    });
    if (isMobile = true) {
        $("#mobile").show();
    }
    else {
        $("#desktop").show();
    }
</script>

Answer 3

你可以试试这个：

LocalDateTime enterDate = LocalDateTime.of(2017, Month.AUGUST, 16, 15, 0); //2017-08-16 15:00:00
LocalDateTime leaveDate = LocalDateTime.of(2017, Month.AUGUST, 17, 12, 0); //2017-08-17 12:00:00

long differnce = enterDate.until(leaveDate, ChronoUnit.HOURS); // 21

你可以根据适合自己的单位来玩Chronounits。

另请查看associate和this