ContentResolver contentResolver1 = getActivity().getContentResolver();
Uri uri1 = MediaStore.Audio.Albums.EXTERNAL_CONTENT_URI;
String[] projection1 = new String[]{MediaStore.Audio.Albums._ID, MediaStore.Audio.Albums.ALBUM_ART};
String selection1 = MediaStore.Audio.Albums._ID + " = ?";
String[] selectionArgs1 = new String[]{String.valueOf(albumId)}; //albumId is MediaStore.Audio.Media.ALBUM_ID
Cursor cursor1 = contentResolver1.query(uri1, projection1, selection1, selectionArgs1, null);
if (cursor1 != null) {
if (cursor1.moveToFirst()) {
String albumPath = cursor1.getString(cursor1.getColumnIndex(MediaStore.Audio.Albums.ALBUM_ART));
if (albumPath != null)
albumArt = BitmapFactory.decodeFile(albumPath);
}
cursor1.close();
}
BitmapFactory.decodeFile(albumPath)
提供FileNotFoundException,即使albumPath
具有以下值 - /storage/emulated/0/Android/data/com.android.providers.media/albumthumbs/1502945757087
关于this answer的评论说明了使用filepath从BitmapFactory.decodeFile()获取位图的同样的事情,这在我的案例中并不起作用。 如何使用上面的路径获取位图?
答案 0 :(得分:0)
试试这个:
Cursor cursor = getActivity().managedQuery(MediaStore.Audio.Albums.EXTERNAL_CONTENT_URI,
new String[] {MediaStore.Audio.Albums._ID, MediaStore.Audio.Albums.ALBUM_ART},
MediaStore.Audio.Albums._ID+ "=?",
new String[] {String.valueOf(id_alnum)},
null);
if (cursor.moveToFirst()) {
String path = cursor.getString(cursor.getColumnIndex(MediaStore.Audio.Albums.ALBUM_ART));
//TODO code
}
答案 1 :(得分:-1)
此示例使用完整文件路径的字符串到您的albumart
public static Bitmap decodeSampledBitmapFromFile(String picture, int reqWidth, int reqHeight) {
// First decode with inJustDecodeBounds=true to check dimensions
final BitmapFactory.Options options = new BitmapFactory.Options();
options.inJustDecodeBounds = true;
BitmapFactory.decodeFile(picture, options);
// Calculate inSampleSize
options.inSampleSize = calculateInSampleSize(options, reqWidth, reqHeight);
// Decode bitmap with inSampleSize set
options.inJustDecodeBounds = false;
return BitmapFactory.decodeFile(picture, options);
}
public static int calculateInSampleSize(
BitmapFactory.Options options, int reqWidth, int reqHeight) {
// Raw height and width of image
final int height = options.outHeight;
final int width = options.outWidth;
int inSampleSize = 1;
if (height > reqHeight || width > reqWidth) {
final int halfHeight = height / 2;
final int halfWidth = width / 2;
// Calculate the largest inSampleSize value that is a power of 2 and keeps both
// height and width larger than the requested height and width.
while ((halfHeight / inSampleSize) >= reqHeight
&& (halfWidth / inSampleSize) >= reqWidth) {
inSampleSize *= 2;
}
}
return inSampleSize;
}
你使用uri的另外一个例子(来源:Lucas Rocha的冰沙):
private Bitmap decodeSampledBitmapFromResource(Uri imageUri, int reqWidth,
int reqHeight) {
InputStream is = null;
try {
is = mContext.getContentResolver().openInputStream(imageUri);
final BitmapFactory.Options options = new BitmapFactory.Options();
options.inJustDecodeBounds = true;
BitmapFactory.decodeStream(is, null, options);
options.inSampleSize = calculateInSampleSize(options, reqWidth,
reqHeight);
options.inJustDecodeBounds = false;
is = mContext.getContentResolver().openInputStream(imageUri);
return BitmapFactory.decodeStream(is, null, options);
} catch (FileNotFoundException e) {
// e.printStackTrace();
return null;
} finally {
try {
if (is != null) {
is.close();
}
} catch (IOException e) {
// e.printStackTrace();
}
}
}
@Override
public Bitmap loadItem(Long id) {
Uri sArtworkUri = Uri.parse("content://media/external/audio/albumart");
Uri imageUri = Uri.withAppendedPath(sArtworkUri, String.valueOf(id));
Resources res = mContext.getResources();
int width = res.getDimensionPixelSize(R.dimen.image_width);
int height = res.getDimensionPixelSize(R.dimen.image_height);
Bitmap bitmap = null;
try {
bitmap = decodeSampledBitmapFromResource(imageUri, width, height);
} catch (Exception e) {
e.printStackTrace();
}
return bitmap;
}
例如,使用uri方法查找id = 3的轨道的albumart:
imageUri = content://media/external/audio/albumart/3
sArtworkUri=content://media/external/audio/albumart
答案 2 :(得分:-2)
您必须申请许可。 你不必得到路径。 请再读一遍
快速的方法是将targetApi降低到22(build.gradle文件)。
或使用新的ask-for-permission模型: