Question

我通过Retrofit的帮助向服务器发送了一个帖子请求，但我希望在服务器发回响应时从令牌中获取值。这是我发送我的帖子请求和onSuccess我希望收到令牌的方式。我的问题是我不知道从服务器响应中检索令牌。请帮助。

public void loginUser(String userName, String userPassword, Boolean userRememberMe) {

    mAPIService.loginUser(userName, userPassword, userRememberMe).enqueue(new Callback<Login>() {
        @Override
        public void onResponse(Response<Login> response, Retrofit retrofit) {
            if(response.isSuccess()) {
                //save token here
                Intent intent = new Intent(LoginActivity.this, ProfileActivity.class);
                startActivity(intent);
            }
        }

        @Override
        public void onFailure(Throwable throwable) {
            Log.e(TAG, "Unable to Login");
        }
    });
}

这是我从服务器获得的回复

{
 "total": 0,
 "data": {
"id": "348680c7-d46b-4adc-9be0-89a1d1a38566",
"username": "0242770336",
"name": "name",
"phoneNumber": "063546345",
"email": "number@gmail.com",
"dateOfBirth": null,
"image": null,
"gender": "",
"idTypeId": null,
"idType": null,
"idNumber": null,
"idExpiryDate": null,
"idVerified": false,
"cityId": null,
"city": null,
"residentialAddress": null,
"latitude": 0,
"longitude": 0,
"createdAt": "2017-08-14T17:45:16.24Z",
"role": {
  "id": 2,
  "name": "User",
  "privileges": [
    ""
  ]
},
"token": "jNK_DGszYOMEpPOFoRGjuyJ5KX9kaJQKCl3cujlHoXklCS8Ij6b-QBmhv0jVwVC54KcNXkzyM62xpswqcjo9Ajf-n-rWzSaIoiYNglaXhtPspziZ0PcTKzTMAvw8si3A7BlcD98M-IjIxYjxieVYAPWVtcvomWi"
},

"message": "Login Successfull",
"success": true
}

这是我的登录模式

public class Login {

@SerializedName("userName")
@Expose
private String userName;
@SerializedName("password")
@Expose
private String password;
@SerializedName("rememberMe")
@Expose
private Boolean rememberMe;

public String getUserName() {
    return userName;
}

public void setUserName(String userName) {
    this.userName = userName;
}

public String getPassword() {
    return password;
}

public void setPassword(String password) {
    this.password = password;
}

public Boolean getRememberMe() {
    return rememberMe;
}

public void setRememberMe(Boolean rememberMe) {
    this.rememberMe = rememberMe;
}

}

Answer 1

有两种方法。

方法1：使用JsonObject

mAPIService.loginUser(userName, userPassword, userRememberMe).enqueue(new Callback<JsonObject>() {
    @Override
public void onResponse(Response<JsonObject> response, Retrofit retrofit) {
       if(response.isSuccess()) {
         try {

           String token=response.body().get("data").get("token");
        } catch (JSONException e) {
              e.printStackTrace();
         }
Intent intent = new Intent(LoginActivity.this,ProfileActivity.class);
startActivity(intent);
    }
}
}

方法2：您可以使用http://pojo.sodhanalibrary.com/将您的回复转换为POJO。现在将它添加到您的项目中，让我们将其命名为ResponseData.class，并通过执行以下更改使用getter方法获取令牌

mAPIService.loginUser(userName, userPassword, userRememberMe).enqueue(new Callback<ResponseData>() {
    @Override
    public void onResponse(Response<ResponseData> response, Retrofit retrofit) {
        if(response.isSuccess()) {
            //save token here
String token =response.getData().getToken();

            Intent intent = new Intent(LoginActivity.this, ProfileActivity.class);
            startActivity(intent);
        }
    }

    @Override
    public void onFailure(Throwable throwable) {
        Log.e(TAG, "Unable to Login");
    }
});

Answer 2

将响应字符串转换为JSONObject，然后再次获取数据的JSONObject，并在数据中找到您的令牌对象。

JSONObject  object  = new JSONObject(response);
JSONObject dataObject = object.getJSONObject("data");
String token = dataObject.getString("token");
Log.i("TAG","token is "+token);

Answer 3

试试这个。

使用optBoolean()方法和optString()方法

try {
        JSONObject jsonObject = new JSONObject(response);
        boolean success = jsonObject.optBoolean("success");
        if (success) {
            JSONObject data = jsonObject.getJSONObject("data");
            String token = data.optString("token");
        } else {
            Log.e("message", "failure");
        }
    } catch (JSONException e) {
        e.printStackTrace();
    }

Answer 4

您可以使用Gson将json转换为Java POJO类。但是，如果您只想获取令牌字段，可以像这样使用它：

public void onResponse(Response<Login> response, Retrofit retrofit) {
        if(response.isSuccess()) {
             try {
        JSONObject ob = new JSONObject(response.body());
        String token = ob.getJSONObject("data").getString("token");

    } catch (JSONException e) {
        e.printStackTrace();
    }
            Intent intent = new Intent(LoginActivity.this, ProfileActivity.class);
            startActivity(intent);
        }
    }

Answer 5

为此你需要先了解这个响应是Json格式的您需要首先从服务器获得的响应中创建Json对象。为了更好地理解https://www.androidhive.info/2012/01/android-json-parsing-tutorial/ http://www.json.org/ 以及获得该响应的代码。

InputGestureText

从JSON中的Server Response获取令牌

5 个答案: