Question

我想从XLM文件中获取带有Xpath的节点列表。我想通过搜索某个属性来获取它们。这是Xml文件。

<ItemGroup>
<Compile Include="Algorithmus_Müllabfuhr\Algorithm.cs" />
<Compile Include="Algorithmus_Müllabfuhr\Tests\AlgorithmTest.cs" />
<Compile Include="Form1.cs">
  <SubType>Form</SubType>
</Compile>
<Compile Include="Form1.Designer.cs">
  <DependentUpon>Form1.cs</DependentUpon>
</Compile>
<Compile Include="Program.cs" />
<Compile Include="Properties\AssemblyInfo.cs" />
<EmbeddedResource Include="Form1.resx">
  <DependentUpon>Form1.cs</DependentUpon>
</EmbeddedResource>
<EmbeddedResource Include="Properties\Resources.resx">
  <Generator>ResXFileCodeGenerator</Generator>
  <LastGenOutput>Resources.Designer.cs</LastGenOutput>
  <SubType>Designer</SubType>
</EmbeddedResource>
<Compile Include="Properties\Resources.Designer.cs">
  <AutoGen>True</AutoGen>
  <DependentUpon>Resources.resx</DependentUpon>
</Compile>
<None Include="packages.config" />
<None Include="Properties\Settings.settings">
  <Generator>SettingsSingleFileGenerator</Generator>
  <LastGenOutput>Settings.Designer.cs</LastGenOutput>
</None>
<Compile Include="Properties\Settings.Designer.cs">
  <AutoGen>True</AutoGen>
  <DependentUpon>Settings.settings</DependentUpon>
  <DesignTimeSharedInput>True</DesignTimeSharedInput>
</Compile>

我的输出应该是

Algorithmus_Müllabfuhr\ Algorithm.cs

Algorithmus_Müllabfuhr\测试\ AlgorithmTest.cs

Form1.cs的

Form1.Designer.cs

Program.cs的

属性\ AssemblyInfo.cs中

Form1.resx中

属性\ Resources.resx

属性\ Resources.Designer.cs

packages.config

属性\ Settings.settings

属性\ Settings.Designer.c

到目前为止，我只搜索带有“Compile”元素的节点。并获得价值。现在我需要从具有属性“Include”的节点获取所有值。

var doc = new XmlDocument();
        doc.Load(csproj.FullName);
        XmlNamespaceManager ns = new XmlNamespaceManager(doc.NameTable);
        ns.AddNamespace("msbld", "http://schemas.microsoft.com/msbuild/2003");
        XmlNodeList xnList = doc.SelectNodes(@"/msbld:Project/msbld:ItemGroup/msbld:Compile", ns);
        foreach (XmlNode node in xnList)
        {
            referencedfiles.Add(new FileInfo(Path.Combine(csproj.Directory.FullName, node.Attributes["Include"].Value)));
        }
        CompareLists(filesinfiles, referencedfiles);

Stackoverflow select all xml nodes which contain a certain attribute 我看了这个帖子，它似乎对我不起作用。我也遇到了XML文档中命名空间的问题。

Answer 1

解决此问题的另一种方法：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml;

namespace Test {
    class Program {
        public static void Main(string[] args)
        {
            XmlDocument doc = new XmlDocument();
            doc.Load("PATHTOXMLFILE");
            List<string> result = RetrieveValues(doc, "Include");
            foreach(string item in result)
            {
                Console.WriteLine(item);
            }
            Console.Read();
        }

        public static List<string> RetrieveValues(XmlDocument doc, string attributeName)
        {
            var list = new List<string>();

            string xpath = @"//*[@" + attributeName + "]";
            XmlNodeList xmlNodeList = doc.SelectNodes(xpath);

            foreach (XmlNode xmlNode in xmlNodeList)
            {
                list.Add(xmlNode.Attributes[attributeName].InnerText);
            }

            return list;
        }
    }
}

希望这有帮助！

通过Attribute从XML文档获取节点

1 个答案: