Question

我有2个包含以下数据的表：

表1（dummy_daily）

Entry               storenum                busidate              daily_budget
1                       1                   2017-07-01               4000
2                       1                   2017-07-02               3500
3                       1                   2017-07-03               2000
4                       1                   2017-07-04               6000
5                       1                   2017-07-05               1500

表2（site_labour）

Lab_id              storenum                busidate              lab_hour
1123                    1                   2017-07-01               128
1124                    1                   2017-07-02               103
1125                    1                   2017-07-03               114
1126                    1                   2017-07-04               108
1127                    1                   2017-07-05               118

这是我当前的查询，用于合并具有相同日期的2个表格，以提供daily_budget和lab_hour的结果 QUERY：

SELECT
a.daily_budget as Ideal, c.lab_hour as Actual,
b.store_name, b.storenum,a.busidate
FROM dummy_daily a JOIN site_store b ON b.storenum=a.storenum JOIN 
site_labour c ON b.storenum=c.storenum
WHERE b.storenum='1' AND 
(CASE WHEN c.busidate BETWEEN '2017-07-01' AND '2017-07-05' THEN c.lab_hour ELSE 0 END) 
AND (CASE WHEN a.busidate 
BETWEEN '2017-07-01' AND '2017-07-05' THEN a.daily_budget ELSE 0 END)

但是我当前的查询给出了错误的结果：

当前查询的错误结果

Ideal          Actual              storenum                 busidate
4000            128                   1                     2017-07-01
3500            128                   1                     2017-07-02
2000            128                   1                     2017-07-03
6000            128                   1                     2017-07-04
1500            103                   1                     2017-07-05
4000            103                   1                     2017-07-01
3500            103                   1                     2017-07-02
2000            103                   1                     2017-07-03
6000            103                   1                     2017-07-04
1500            103                   1                     2017-07-05

此数据将持续到实际118结束

预期结果

Ideal          Actual              storenum                 busidate
4000            128                   1                     2017-07-01
3500            103                   1                     2017-07-02
2000            114                   1                     2017-07-03
6000            108                   1                     2017-07-04
1500            118                   1                     2017-07-05

Answer 1

让我们尝试下面的SQL：

SELECT
a.daily_budget as Ideal, c.lab_hour as Actual,
b.store_name, b.storenum,a.busidate
FROM dummy_daily a JOIN site_store b ON b.storenum=a.storenum AND b.busidate=a.busidate JOIN 
site_labour c ON b.storenum=c.storenum AND b.busidate=c.busidate
WHERE b.storenum='1' AND 
(CASE WHEN c.busidate BETWEEN '2017-07-01' AND '2017-07-05' THEN c.lab_hour ELSE 0 END) 
AND (CASE WHEN a.busidate 
BETWEEN '2017-07-01' AND '2017-07-05' THEN a.daily_budget ELSE 0 END)

Answer 2

你错过了另外一张桌子，因此制造逻辑会造成混乱，根据我的理解，我创建了一个SELECT语句。请试试这个： -

    SELECT 
    dummy_daily.daily_budget as Ideal, site_labour.lab_hour as Actual,
    site_store.store_name, site_store.storenum, dummy_daily.busidate
    FROM dummy_daily 
    JOIN site_store 
    ON dummy_daily.storenum = site_store.storenum
    JOIN site_labour
    ON dummy_daily.storenum = site_labour.storenum
    WHERE (dummy_daily.storenum = 1)
    AND (dummy_daily.busidate BETWEEN '2017-07-01' AND '2017-07-05')
    AND (site_labour.busidate BETWEEN '2017-07-01' AND '2017-07-05')
    AND (dummy_daily.busidate = site_labour.busidate);

如何组合2个具有相同日期的表

2 个答案: