Question

当我在tinymce中添加图像时，这是我得到的默认html源代码：

<p><img class="img-responsive img-post" src="/Images/uploads/img.png" alt="" /></p>

我该如何改变？类似于：

<p><img class="img-responsive img-post" data-original="/Images/uploads/img.png" src="/Images/loading.gif" alt="" /></p>

我的数据是原始的，因为src和src是加载图标，它需要是这样的，因为我在图像上有延迟加载。

我知道您可以使用以下方法扩展有效元素：

extend_valid_elements: "data-original"

但是如何更改默认html源代码的结构？有没有像选择ok for image insert callback ??

更新

这是我的启动代码：

/******************************tinyMce*******************************/
function tinyMce() {
    tinymce.init({
        theme: "modern",
        selector: "#mceEditor",
        height: 500,
        extend_valid_elements: "data-original",
        relative_urls: true,
        convert_urls: false,
        image_advtab: true,
        image_title: false,
        image_description: false,
        image_dimensions: false,
        image_class_list: [
            { title: "Responsive", value: "lazy img-responsive img-post" }
        ],
        image_list: function (success) {
            $.ajax({
                url: "/Image/List",
                type: "GET",
                dataType: "json",
                success: function (data) {
                    success(data);
                }
            });
        },
        // enable automatic uploads of images represented by blob or data URIs
        automatic_uploads: true,
        // URL of our upload handler (for more details check: https://www.tinymce.com/docs/configure/file-image-upload/#images_upload_url)
        images_upload_url: "/Image/Upload",
        // here we add custom filepicker only to Image dialog
        file_picker_types: "image",
        // and here's our custom image picker
        file_picker_callback: function (cb, value, meta) {
            var input = document.createElement("input");
            input.setAttribute("type", "file");
            input.setAttribute("accept", "image/*");

            // Note: In modern browsers input[type="file"] is functional without 
            // even adding it to the DOM, but that might not be the case in some older
            // or quirky browsers like IE, so you might want to add it to the DOM
            // just in case, and visually hide it. And do not forget do remove it
            // once you do not need it anymore.

            input.onchange = function () {
                var file = this.files[0];

                var reader = new FileReader();
                reader.readAsDataURL(file);
                reader.onload = function () {
                    // Note: Now we need to register the blob in TinyMCEs image blob
                    // registry. In the next release this part hopefully won't be
                    // necessary, as we are looking to handle it internally.
                    var id = "blobid" + (new Date()).getTime();
                    var blobCache = tinymce.activeEditor.editorUpload.blobCache;
                    var base64 = reader.result.split(',')[1];
                    var blobInfo = blobCache.create(id, file, base64);
                    blobCache.add(blobInfo);

                    // call the callback and populate the Title field with the file name
                    cb(blobInfo.blobUri(), { title: file.name });
                };
            };

            input.click();
        }
    });
}

我正在考虑另一种方式，如果我可以将tinymce中的默认src属性替换为数据原始，那将是完美的，但在内部，如果我使用数据原始，它不会显示图片，它只显示空白。有没有办法在添加图像时告诉tinymce，将数据原始而不是src放入并从数据原始而不是src读取？

因此：

<p><img class="img-responsive img-post" src="/Images/uploads/img.png" alt="" /></p>

对此没有src：

<p><img class="img-responsive img-post" data-original="/Images/uploads/img.png" alt="" /</p>

Answer 1

这是一种检测图像何时插入编辑器的方法。

JS

var newSrc = "/Images/loading.gif";


tinymce.init({
  selector: 'textarea',
  plugins: "image",
  toolbar: "image",
  height: 350,
    setup: function(editor){
    editor.on('NodeChange', function (e) {
      if(e.element.tagName === "IMG"){          
        e.element.setAttribute("data-original", e.element.currentSrc);
        e.element.setAttribute("src", newSrc);
      }
    });
  }
});

您可以通过收听NodeChange事件来访问该元素。然后检查tagName的类型为IMG。然后我们只是正常设置我们的属性。

选中此Demo

Answer 2

...但在内部，如果我使用数据原创，它不会显示图片，它只显示空白。

继续做你在这里做的事情，只需添加一个更改处理程序来添加新的src ...

editor.on('Change', function (e) {
    // Get images that have data-original attribute but not src
    $( 'img[data-original]' ).not( 'img[src]' )
      .attr( 'src', '/Images/loading.gif' ) // Add src
} );

Answer 3

您可以使用正则表达式和字符串replace method解决此问题该函数将返回匹配的替换..如下例所示

// tinymce returning string
let content = '<p><img class="img-responsive img-post" src="/Images/uploads/img.png" alt="" /></p><p><img class="img-responsive img-post" src="/Images/uploads/img2.png" alt="" /></p>';

// searching through all the img tags in the content..
content = content.replace(/<img(\s+[^>]*)src="([^"]*)"([^>]*)>/g,function(full,key, value){
 return `<img ${key} src="/Images/loading.gif" data-original="${value}" alt="">`;
});


//content replaced
console.log(content);

正则表达式用于匹配所有img标记，然后我们只是新的data-original属性并将其替换为原始字符串

如何更改在Tinymce中添加图像的默认html

3 个答案: